See the attached picture:
1. 437,000,003,000,000
2. 53,000,200
3. 797,619,000,000,132
4. 11,006,007
5. 84,000,037,800
36 is not prime it is composite
The values of x that will give the quadratic equation no real number solutions are -5 and 9
<h3>What are real roots of a quadratic equation?</h3>
Real roots of a quadratic equation are values of x, whose numbers can be represented on a number line.
Analysis:
We have -
+3x +c = 0
- 4ac is called the discriminant of a quadratic equation.
if
- 4ac < 0, then the quadratic equation has no real root.
where a = -1, b = 3 c = c
-4(-1)c < 0
9 + 4c < 0
4c < -9
c < -9/2
Which means values lower than -9/2 would give the solution no real root.
From, the options, only -5 would give no real solution, since it is lower than -9/2.
Learn more about real roots of a quadratic equation: brainly.com/question/7784687
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Answer:
y=-2+3 y-intercept = (0,3)
y=3x=3 = ???? there cant be 2 equal signs so i cant help with that question
Step-by-step explanation: