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4 years ago

Dilations help me please

Mathematics

1 answer:

8_murik_8 [283]4 years ago

5 0

Answer:

D'(1, - 1 )

Step-by-step explanation:

Assuming the dilatation is centred at the origin, then multiply the coordinates of D by $\frac{1}{2}$ , that is

D(2, - 2 ) → D'( $\frac{1}{2}$ (2) , $\frac{1}{2}$ (- 2) ) → D'(1, - 1 )

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Help, with math! due soon!

inn [45]

Answer:

a) (4, 5)

b) (3, -1)

c) (4, 4)

d) (-3, 2)

e) (3, 1)

f) (7, 8)

Step-by-step explanation:

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3 0

2 years ago

What value of x satisfies this equation, 4/5 x - 6 = -2 ? Group of answer choices

andrew11 [14]

Answer:

Step-by-step explanation:

4/5 x -6 = -2

4 x -30 = -10

-120 = -10

5 0

3 years ago

3x − x − 1 = 15<br> What is x

azamat

Answer: x=8

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x−x−1=15

3x+−x+−1=15

(3x+−x)+(−1)=15(Combine Like Terms)

2x+−1=15

2x−1=15

Step 2: Add 1 to both sides.

2x−1+1=15+1

2x=16

Step 3: Divide both sides by 2.

2x /2 = 16 /2

x=8

4 0

3 years ago

Read 2 more answers

Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1. (2 points)

umka2103 [35]

Focus of the parabola is (-5,5) and directrix is y = -1.

Let's assume a point (x,y) on parabola.

According to definition of parabola, the distance between point (x,y) and focus (-5,5) would be same as the distance between the point (x,y) and directrix y = -1.

$\sqrt{(x+5)^2+(y-5)^2} = \sqrt{(y+1)^2} \\\\(x+5)^2+(y-5)^2=(y+1)^2 \\\\(x+5)^2 + y^2 - 10y +25 = y^2 +2y +1 \\\\(x+5)^2 = -y^2 +10y -25 + y^2 +2y +1 \\\\(x+5)^2 = 12y -24 \\\\12y = (x+5)^2 +24 \\\\ y = \frac{1}{12} (x+5)^2 +2$