Answer: D: s∈ (-∞, 3]
Step-by-step explanation:
When we have a function:
y = f(x)
The domain is the set of the possible values we can input in f(x).
In this case, we have:
y = √(3 - s)
Where our variable is s.
So we want to find the possible values of s we can input in that function.
Remember that if y is a real number, then we can not have a negative number inside the square root, because it will lead to an complex solution.
Then the argument of the square root needs to be equal to or larger than zero.
This means that:
3 - s ≥ 0
From this inequality, we can find the possible values of s, which will be the domain.
We need to isolate s.
3 ≥ s
This means that s needs to be smaller than or equal to 3.
Then the domain is:
D: s∈ (-∞, 3]
The first figure below shows the graph for problem 5).
The second figure below shows the graph for problem 6).
Answer:
y=tan x and y=cotx
Step-by-step explanation:
We are given functions of all trignometric ratios and asked to find out which has range of all real numbers. Let us discuss one by one
1. y =sinx: False because -1≤sinx≤1 always
2. y=cosx:False because -1≤cosx≤1 always
3. y = tanx: True because tanx can take any value
4. y=cot x: True because cots x can take any value
5. y = csc x: False because this range does not lie between -1 and 1
6. y=sec xFalse because this range does not lie between -1 and 1
D) 40% 2/5=40 so 40 percent chance
Answer:
D.
Step-by-step explanation:
Simply plug in your variables and solve (<em>r </em>= x + 2 and <em>h</em> = 3x + 8):
V = π(x + 2)²(3x + 8)
V = π(x² + 4x + 4)(3x + 8)
V = π(3x³ + 20x² + 44x + 32)
V = 3x³π + 20x²π + 44xπ + 32π