Answer:
C 120
Step-by-step explanation:
120 because 60/3=20 so 20x 6=120
Hope that helped
Answer:
5
Step-by-step explanation:
Answer:
You are given:
4Fe+3O_2 -> 2Fe_2O_3
4:Fe:4
6:O_2:6
You actually have the same number of Fe on both sides, The same is true for O_2 so yes this equation is properly balanced.
For added benefit consider the following equation:
CH_4+O_2-> CO_2+2H_2O
ASK: Is this equation balanced? Quick answer: No
ASK: So how do we know and how do we then balance it?
DO: Count the number of each atom type you have on each side of the equation:
1:C:1
4:H:4
2:O:4
As you can see everything is balanced except for O To balance O we can simply add a coefficient of 2 in front of O_2 on the left side which would result in 4 O atoms:
CH_4+color(red)(2)O_2-> CO_2+2H_2O
1:C:1
4:H:4
4:O:4
Everything is now balanced.
Step-by-step explanation:
The square root of 125 is in between 11 and 12. It is 11.1803.
Lateral Area, namely the area of its sides, namely excluding its base.
well, the pyramid is standing on one of its triangular faces, so we'll have to exclude that.
now, let's notice, is a square pyramid, so it has an 8x8 square, and it has triangular faces that have a <u>base of 8 and a height of 22</u>.
![\bf \stackrel{\textit{square's area}}{(8\cdot 8)}~~+~~\stackrel{\textit{3 triangular faces' area}}{3\left[ \cfrac{1}{2}(8)(22) \right]}\implies 64+264\implies 328](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bsquare%27s%20area%7D%7D%7B%288%5Ccdot%208%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7B3%20triangular%20faces%27%20area%7D%7D%7B3%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%288%29%2822%29%20%5Cright%5D%7D%5Cimplies%2064%2B264%5Cimplies%20328)
