because if you multiply 3 by 0 its the same thing as saying 0+0+0 and that is still 0 (hope this was helpful)
Answer:
Step-by-step explanation:
We are to rank the options given in the question to correctly prove the theorem that: "If A & B are set, and A is a subset of B"
To arrange the steps in the correct order, we have:
(a) Assume that B is countable
(b) The elements of B can be listed as b1, b2, b3
(c) Since A is a subset of B, taking the subsequence of {bn} that contains the terms that are in A gives a listing of the elements of A.
(d) Therefore A is countable, contradicting the hypothesis.
(e) Thus B is not countable
Answer:
Step-by-step explanation:
xxcSD1EA
-1 55/100 then reduce, -1 11/20
9514 1404 393
Answer:
D.) a+2b
Step-by-step explanation:
The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...
A) 3(0) = 0 . . . even
B) 1 +3 = 4 . . . even
C) 2(1+0) = 2 . . . even
D) 1 +2(0) = 1 . . . odd
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<em>Additional comment</em>
These rules apply to even/odd:
- odd × odd = odd
- odd × even = even
- even × even = even
- odd + odd = even
- odd + even = odd
- even + even = even
Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.
