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Brilliant_brown [7]
3 years ago
14

Isaiah puts a 10 gram weight on a pan balance.how many 1-gram weights does he need to balance the scale

Mathematics
1 answer:
Vikki [24]3 years ago
6 0
<span>Isaiah puts a 10 gram weight on a pan balance. To balance the scale, he needs to put 10 pieces of 1 gram weights which will be equivalent to 10 grams of weight. Hope this answers the question. Have a nice day.</span>
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What fractional part of a pound is an ounce
marysya [2.9K]
One ounce is one-sixteenth of a pound since there is 16 ounces in a pound. 
6 0
3 years ago
Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

6 0
3 years ago
the areas of the world's oceans are listed in the table order the oceans according to their area from least to greatest.
agasfer [191]
Pacific ocean is the biggest ocean
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3 years ago
Help meeeee and plz get it right
Maslowich
The answer is The first one A
5 0
3 years ago
Please help
jonny [76]

Answer:

4. y = 1/2x + 3/2

Step-by-step explanation:

First, we need to change the line that's parallel into slope-intercept form.

-2x + 4y = 8

4y = 2x + 8

y = 1/2x + 2

If it's parallel, then it remains the same. So our slope is 1/2.

To find the y-intercept, you need to plug the coordinates into the equation.

y = 1/2x + b

-1 = 1/2(-5) + b

-1 = -5/2 + b

3/2 = b

y = 1/2x + 3/2

6 0
3 years ago
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