-2 dropped in that hour of time
Answer: Our required probability is 0.83.
Step-by-step explanation:
Since we have given that
Number of dices = 2
Number of fair dice = 1
Probability of getting a fair dice P(E₁) = 
Number of unfair dice = 1
Probability of getting a unfair dice P(E₂) = 
Probability of getting a 3 for the fair dice P(A|E₁)= 
Probability of getting a 3 for the unfair dice P(A|E₂) = 
So, we need to find the probability that the die he rolled is fair given that the outcome is 3.
So, we will use "Bayes theorem":

Hence, our required probability is 0.83.
9m+14=2m
9m-2m= -14
7m = -14
m= -2
to check: u need to chance the m to -2
9m - 2m= -14
9 × -2= -18
-2 × -2= -4
-18 - (-4)= -14
i think is right