If f(x) = x^2 is vertically compressed by a factor of 8 to g(x) what is the equation of g(x)?

Mathematics

1 answer:

Nadya [2.5K]2 years ago

7 0

Answer: First option

$g(x) = \frac{1}{8}x^2$

Step-by-step explanation:

Step-by-step explanation:

If the graph of the function $y=cf(x)$ represents the transformations made to the graph of $y= f(x)$ then, by definition:

If $0$ then the graph is compressed vertically by a factor c.

If $|c| > 1$ then the graph is stretched vertically by a factor c

If $c$ then the graph is reflected on the x axis.

In this problem we have the function $f(x)=x^2$ If this function is vertically compressed by a factor of 8 then $0$ and $c=\frac{1}{8}$

Therefore the graph of g(x) is $g(x)=\frac{1}{8}f(x)$

$g(x) = \frac{1}{8}x^2$

The answer is the first option

You might be interested in

How do i check an equation for extraneous solutions?

Marina86 [1]

Example:

$\sqrt x(x+1)=0$

This suggests two solutions, $x=0$ and $x=-1$ .

However, upon plugging these solutions back into the equation, you get

$\sqrt0(0+1)=0(1)=0$

which checks out, but

$\sqrt{-1}(1-1)=0$

does not because $\sqrt x$ is defined only for $x\ge0$ (assuming you're looking for real solutions only). So, we call $x=-1$ an extraneous solution, and the complete solution set (over the real numbers) is $x=0$ .

7 0

3 years ago

Read 2 more answers

Find an equation of a sphere if one of its diameters has endpoints (3, 2, 5) and (5, 6, 7). Incorrect: your answer is incorrect.

prohojiy [21]

use midpoint equation

radius = distance between midpoint and one of the endpoints.

midpoint: (3+5)/2, (2+6)/2, (5+7)/2 = (4,4,6)

equation of sphere: (x-4)^2 + (y-4)^2 + (z-6)^2 = r^2

square distance between midpoint and one of the endpoints.

r^2 = 6

Equation: (x-4)^2 + (y-4)^2 + (z-6)^2 = 6