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trapecia [35]
3 years ago
8

If f(x) = x^2 is vertically compressed by a factor of 8 to g(x) what is the equation of g(x)?

Mathematics
1 answer:
Nadya [2.5K]3 years ago
7 0

Answer: First option

g(x) = \frac{1}{8}x^2

Step-by-step explanation:

Step-by-step explanation:

If the graph of the function y=cf(x)  represents the transformations made to the graph of y= f(x)  then, by definition:

If  0 then the graph is compressed vertically by a factor c.

If  |c| > 1 then the graph is stretched vertically by a factor c

If c  then the graph is reflected on the x axis.

In this problem we have the function f(x)=x^2 If this function is vertically compressed by a factor of 8 then  0  and c=\frac{1}{8}

Therefore the graph of g(x) is  g(x)=\frac{1}{8}f(x)

g(x) = \frac{1}{8}x^2

The answer is the first option

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the function v(t)=-9.8t+5 gives the instantaneous velocity of an object thrown upward with an initial velocity of 5 m/sec. at wh
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Answer:

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Let's see what each term in the function v (t) = - 9.8t + 5 means:

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        The variable t is the time

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Hence the equation tells that after the object was launched upward it starts to lose speed and will reach a maximum height when the velocity is equal to zero, from which it starts falling.

So, you can calculate when the object reachs it maximum height and starts falling by making the velocity, v (t), equal to zero and solving for t. This is how you do it:

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  • t = 5 m/s / 9.8 m/s² = 0.51 s

So, the object starts fallin at 0.51 s. Since, the velocity is reported with 1 significant digit you answer should also show 1 significant digit, which means t = 0.5 s.

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