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m_a_m_a [10]
3 years ago
6

Stephan added 26 new contacts to his phone list. He had to delete 16 old contacts before he could add any more. Stefan now has a

total of 100 contacts. Let c represent how many contacts he had on his phone list before he updated it. Write an equation and then solve for c.
Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0

Answer: 90c-16c+26c=100c

Stephan had 90 contacts before he deleted 16 then added 26 more how it works is Stephan had 90 right, then proceeded to delete 16 which left him with 74 contacts after he then added 26 more contacts so he know has 100 contacts.

bezimeni [28]3 years ago
5 0

Answer: 26-16= c

c=10

Step-by-step explanation:

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How is 2-2×6+3=-7?<br>The answer to this question​
alekssr [168]

Answer:

PEMDAS

Step-by-step explanation:

Using PEMDAS or the order of operations, you first multiply 2 by 6

2-2×6+3

2-12+3  

Then you can go in any order since addition and subtraction take the same precedence.

-10+3=-7

5 0
3 years ago
Charlotte’s weekly paycheck is based on the number of hours worked during the week and on the weekend. If she works 13 hours dur
Schach [20]
X: earn per  hour during the week
y: earn per hour during the weekend

13x + 14y = 250.90
15x + 8y = 204.70

Multiply the first equation by 4 and the second equation by 7

52x + 56y = 1003.6
105x + 56y = 1432.90

Subtract the first equation from the second:

 53x = 429.30

x = 429.30/ 53
x = 8.10

Solve any of the equation for y:

15x + 8y = 204.70

y = [204.70 - 15(8.10)]/8 = 10.40

y - x = 10.40 -8.10 = 2.30

Answer: she earns $2.30 per hour more during the weekend than during the week.


8 0
3 years ago
Read 2 more answers
HELP PLEASE,<br><br> Part a of the question was posted earlier on.
Elanso [62]
\bf \lim\limits_{x\to 6}~\cfrac{x^2+x+42}{x-6}\implies \lim\limits_{x\to 6}~\cfrac{(x+7)(x-6)}{(x-6)}\implies \lim\limits_{x\to 6}~x+7&#10;\\\\\\&#10;\lim\limits_{x\to 6}~(6)+7=13&#10;\\\\\\&#10;\textit{since the original equation holds for all, }x\ne 6,\textit{ then it approaches}\\&#10;\textit{the same limit as }x+7
3 0
3 years ago
You multiply two integers. You increase one of them by 1 and decrease the other
snow_tiger [21]

Integers are numbers without decimals

The integers could you have multiplied are 9 and 2

Let the numbers be x and y

So, we have:

\mathbf{x \times y}

Increase x by 1 and reduce y by 1.

So, we have

\mathbf{(x +1) \times (y -1) = 6 + xy }

Open brackets

\mathbf{xy -x + y - 1 = 6 + xy}

Subtract xy from both sides

\mathbf{ -x + y - 1 = 6}

Collect like terms

\mathbf{ -x + y = 6 + 1}

\mathbf{ -x + y = 7}

Rewrite as:

\mathbf{ y -x= 7}

The above means that, the difference between the integers is 7.

There are several integers that fit the above <em>description</em>;

One possibility is: 9 and 2

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brainly.com/question/3208278

6 0
2 years ago
Round 0.598 to the nearest hundredth.
Assoli18 [71]

Answer:

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Step-by-step explanation:I need brainliest for the next rank I’d appreciate it

5 0
3 years ago
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