Answer:
80π
Step-by-step explanation:
Circle O with radius IO:
large radius = IO = 12 = R
Circle O with diameter JK
IJ = JK = KL = 2 × IO = 24
IJ = JK = KL = 24/3 = 8
small radius = 8/2 = 4 = r
The shaded area is a semicircle of radius 12 minus a semicircle of radius 4 plus two semicircles of radius 4.
That is the same as
1 semicircle of radius 12 plus 1 semicircle of radius 4
A = πR²/2 + πr²/2
A = π(12² + 4²)/2
A = 160π/2
A = 80π
Answer:
how would you classify this triangle? remember you need two names.
For short you call this scientific notation.
FIRST
Count how many time you need to move the decimal over to make your single digit more then 1 and less then 10. So we will erase the 0's as we go along.
167000,000,000,000
So in this case we want to make the single digit 1.67 so it can be greater then 1 and less then 10
So now we see how many times we need to move the decimal and when you cant see the decimal just imagine it at the very end of the problem
167000,000,000,000
(For the mods out there I copied and pasted the bold number so i didn't have to take a while to retype the whole number. Thanks.)
SO NOW I get 14 because that's how many spots the decimal moved over.
Now since we need to right it in SN we need to write out this
X*10^X
The exponent X stands for how many times we moved the decimal over. I got 14 so we have that exponent
X*10^14
NOW We need to fiqure out X.... X was just the number we made greater then one and less then 0.
So thats 1.67
So we get
1.67*10^14
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