Answer:

Step-by-step explanation:
The given functions are:
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and

Now,


The domain refers to values of
for which
is defined.
The expression under the radical sign must not be negative.
The domain is

3x+15x = 180
18x = 180
x = 10
10(x+y) + 3x = 180
10x + 10y + 3x = 180
13x + 10y = 180
13(10) + 10y = 180
130 + 10y = 180
10y = 50
y = 5
The X coordinate has to be 0
Answer: Question 1 :B,D.
Question 2:option B,
Question 3:Degree=5.
Question 4:option D.
Question 5: option c.
Step-by-step explanation:
1) A polynomial can not have any exponent as a variable or a fraction.
Options B and D are polynomials.
2) The polynomial is having 3 terms and is of degree 3.so it is a cubic trinomial Option B.
3) Degree is the highest power of the variables in the terms .The term
has the power=3+2=5
So degree =5.
4)
Option D
5)
Simplifying like terms,
=
Option c.
Answer:
Step-by-step explanation:
Michael is using a number line to evaluate the expression -8 - 3. After locating -8 on the number line , Michael could rewrite the expression as -8 + -3 and move 3 spaces to the left.