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Neko [114]
3 years ago
12

One serving of rice has 44.9 grams of carbohydrates how many grams of carbohydrates de 2.5 servings of rice have

Mathematics
1 answer:
Fofino [41]3 years ago
4 0

Answer:

112.25\ grams\ of\ carbohydrates    

Step-by-step explanation:

we know that

using proportion

\frac{1}{44.9}\frac{serving\ of\ rice}{grams\ of\ carbohydrates} =\frac{2.5}{x}\frac{serving\ of\ rice}{grams\ of\ carbohydrates} \\ \\x=44.9*2.5\\ \\x=112.25\ grams\ of\ carbohydrates

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Answer:

Swimming one time around the pool is 56.5 ft

Step-by-step explanation:

Swimming 18 ft from one side of her circular pool to the other, swimming straight through the center means the circular swimming pool has a diameter of d=18 ft.

The circumference of the circle is calculated using:

c = \pi \: d

where d=18 is the diameter and π=3.14 as given.

We substitute the values to get:

c = 3.14 \times 18

c = 56.52

We approximate to the nearest tenth to get:

c = 56.5ft

6 0
3 years ago
DO 11. Find the slope of the line that passes through the points<br> (-4, 7/2) and (3, -21/10)
Evgen [1.6K]

Answer:

-4/5

Step-by-step explanation:

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2 years ago
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marysya [2.9K]

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Step-by-step explanation:

7 0
3 years ago
A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a
kiruha [24]

Answer:

407 mi/h

Step-by-step explanation:

Given:

Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, s=\frac{dx}{dt}=470\ mi/h

Now, applying Pythagoras theorem to the triangle, we have:

D^2=h^2+x^2\\\\D^2=1+x^2

Differentiating with respect to time 't', we get:

2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi

Now, plug in all the given values and solve for \frac{dD}{dt}. This gives,

\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

6 0
3 years ago
Solve the system of equations. 8x – 3y = 1 –2x + 3y = 11 A. (–1, –3) B. (–1, 3) C. (2, 5) D. (5, 2)
Makovka662 [10]

Answer:

C. (2, 5)

Step-by-step explanation:

Looking at the answer choices, you can see that solving for y will tell you which choice is correct. We can eliminate x from the equations by adding 4 times the second equation to the first:

(8x -3y) +4(-2x +3y) = (1) +4(11) . . . . . adding the equations to eliminate x

9y = 45 . . . simplified; next we divide by 9

y = 5 . . . . . matches choice C

_____

Check

8(2) -3(5) = 16 -15 = 1

-2(2) +3(5) = -4 +15 = 11 . . . . the answer checks OK in both equations

4 0
3 years ago
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