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Vedmedyk [2.9K]
3 years ago
6

It is given 5 and h + 1 are the roots of the quadratic equation x² + (k - 1)x - 5 = 0,where h and k are constant.Find the value

of h and k.
pls help me,i'll mark u as the brainliest!​
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0

Answer:

Hello,

<u>k=-3 and h=-2</u>

Step-by-step explanation:

5\ is\ a \ root \of \ x^2+(k-1)*x-5=0\\\\5^2+(k-1)*5-5=0\\\\5*(k-1)+20=0\\\\k-1=\dfrac{-20}{5} \\\\k=-4+1\\\\\boxed{k=-3}\\

h+1 is thus a root of x²+(-3-1)*x-5=0

x²-4x-5=0

x²+x-5x-5=0

x(x+1)-5(x+1)=0

(x+1)(x-5)=0

h+1=-1

<u>h=-2</u>

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Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.
gizmo_the_mogwai [7]

Answer:

When y=32, x=16.5

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Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

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x varies inversely with y

We can write it as: x\:\alpha \:\frac{1}{y}

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Put the given numbers in the relevant formula and do the arithmetic.

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   V = πr²h = 3.14(4 cm)²(3 cm) = 3.14×48 cm³ = 150.72 cm³

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  V = 1/3πr²h = 1/3(3.14)(5 cm)²(12 cm) = 3.14×100 cm³ = 314 cm³

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