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Vedmedyk [2.9K]
3 years ago
6

It is given 5 and h + 1 are the roots of the quadratic equation x² + (k - 1)x - 5 = 0,where h and k are constant.Find the value

of h and k.
pls help me,i'll mark u as the brainliest!​
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
6 0

Answer:

Hello,

<u>k=-3 and h=-2</u>

Step-by-step explanation:

5\ is\ a \ root \of \ x^2+(k-1)*x-5=0\\\\5^2+(k-1)*5-5=0\\\\5*(k-1)+20=0\\\\k-1=\dfrac{-20}{5} \\\\k=-4+1\\\\\boxed{k=-3}\\

h+1 is thus a root of x²+(-3-1)*x-5=0

x²-4x-5=0

x²+x-5x-5=0

x(x+1)-5(x+1)=0

(x+1)(x-5)=0

h+1=-1

<u>h=-2</u>

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Diego was trying to write (5^2)^4 with a single exponent and wrote (5^2)^4=5^2+^4=5^6. What should the answer be? Explain Diego'
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Step-by-step explanation:

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As the first term is 4 and next term is obtained by adding 4 to the first term.

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<em>So, f(n) = f(n-1) + 4 would be the correct recursive formula for the function of the sequence 4, 8, 12, .... </em>

<em>Verification: </em>

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<em>                f(2) = f(2-1) + 4</em>

<em>                f(2) = f(1) + 4</em>

<em>                f(2) = 4 + 4</em>

<em>                f(2) = 8</em>

Putting n=3 in f(n) = f(n-1) + 4 to get the third term of the sequence.

<em>                 f(3) = f(3-1) + 4</em>

<em>                 f(3) = f(2) + 4</em>

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<em>                f(3) = 8 + 4</em>

<em>                 f(3) = 12</em>

<em />

Keywords: recursive formula, sequence

Learn more about using recursive formula from brainly.com/question/1851471

#learnwithBrainly<em> </em>

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