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Bad White [126]
3 years ago
6

Which image shows the correct position of M(-4, 3)?

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:A

Step-by-step explanation: In (-4,3) -4 is the value of x and 3 is the value of y

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I need help with this and uh can u tell me/ show your work in the answer?
julsineya [31]

Answer:

They should insert that y value into the other equation.

Step-by-step explanation:

7 0
3 years ago
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A quadratic function passes through the points ( − 5 , − 8 ) and ( 8 , − 8 ) . Find the equation for the line (axis) of symmetry
ra1l [238]

Answer:

The equation for the axis of symmetry is x=1.5.

Step-by-step explanation:

It is given that a quadratic function passes through the points ( − 5 , − 8 ) and ( 8 , − 8 ) .

In the given points y-coordinates are same, i.e., -8. It means both the points lie on the horizontal line y=-8.

If a quadratic function passes through two points (a,c) and (b,c), then the equation for the axis of symmetry is

x=\frac{a+b}{2}

According to the given points a=-5, b=8 and c=-8. Put these value in the above formula.

x=\frac{-5+8}{2}

x=\frac{3}{2}

x=1.5

Therefore the equation for the axis of symmetry is x=1.5.

8 0
3 years ago
A standard stop sign measures 30.00 inches from flat to flat. What is the side length, x, of the stop sign (to the nearest 0.01
Lorico [155]

Answer: 254

Step-by-step explanation:

3 0
3 years ago
Describe the image when a scalene triangle is rotated 180 degrees counterclockwise
Luba_88 [7]

Answer:

It is a same size scalene triangle as the original triangle.

Step-by-step explanation:

:)

6 0
2 years ago
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Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
2 years ago
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