Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
Answer:
a. 122 degree is the answer
I think we will need to use the 1mile=5280ft and the 1ft=30.48cm and the 1metre=100cm
so
3/4 mles=3/4 times 5280=3960ft
1ft=30.48cm
times both sides by 3960
3960ft=120700.8cm
1metre=100cm
1/100meter=1cm
times both sides by 120700.8
1207.008meter=120700.8cm=3/4mile
answer is 1207.008 meters
round
1207 meters
Answer:
I think it would be 8
Step-by-step explanation:
Simplify 1/4y - 8y2
x = -8y2 + y/4
Answer:
The nose will 2.75 meters long.
Step-by-step explanation: