It would be estimated about 2,100 trouts I would say, since 7,500 divided by 50 is 150 so 150 x 14 = 2,100 trouts :)
Answer, step-by-step explanation:
A. With the previous exercise we can deduce that there is the situation of a number of sales in a grocery store, the relative frequency for the number of units sold, is shown below:
units sold. relative frequency. Acumulative frequency. interval of random numbers
30. 0.16. 0.16. 0.00 <0.16
40. 0.24. 0.4. 0.16 <0.4
50. 0.3. 0.7. 0.4 <0.7
60. 0.2. 0.9. 0.7<09
70. 0.1. 1. 0.9<1
B. For the next point, they give us some random numbers and then it is compared with the simulation of 10 days in sales:
random Units
number. sold
0.12. 30
0.96. 70
0.53. 50
0.80. 60
0.95. 70
0.10. 30
0.40. 50
0.45. 50
0.77. 60
0.29. 40
the two lists are compared so that opposite each one is the result of the simulation
Where x is 4 the corresponding y is 5. Your answer is 5.
Answer:
0.3
Step-by-step explanation:
To find p we require the cube root of 0.027, that is
p³ = 0.027, then
p = ![\sqrt[3]{0.027}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.027%7D)
= ![\sqrt[3]{\frac{27}{1000} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B27%7D%7B1000%7D%20%7D)
= 
= 0.3
