<span>Orbital radius would decrease because the gravitational pull would increase.</span>
<span>3.834 m/s.
In this problem we need to have a centripetal force that is at least as great as the gravitational attraction the object has. The equation for centripetal force is
F = mv^2/r
and the equation for gravitational attraction is
F = ma
Since m is the same in both cases, we can cancel it out and then set the equations equal to each other, so
a = v^2/r
Substitute the known values (radius is diameter/2) and solve for v
9.8 m/s^2 <= v^2/1.5 m
14.7 m^2/s^2 <= v^2
3.834057903 m/s <= v
So the minimum velocity needed is 3.834 m/s.</span>
Answer:
The answer to the question is
The luminosity of stars A is four times that of star B
Explanation:
Flux (F) produced by a source of light is directly proportional to the brightness or Luminosity (L), and varies inversely to its distance d, that is 
Therefore if the two stars present the same flux then we have
then crossing out like terms gives 
or 4·L₁ = L₂
The luminosity of star A is 4 times the that of star B
