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ollegr [7]
2 years ago
10

Please help me with the question below

Physics
1 answer:
vampirchik [111]2 years ago
6 0

Answer:

a cold air mass and a warm air mass merge together

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Which model could represent a neutral atom of boron?
UNO [17]

Answer:

model 3

Explanation:

Boron with atomic number 5 will have 3 valence electrons

5 0
3 years ago
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An object initially at rest experiences an acceleration of 1.90 ­m/s² for 6.60 s then travels at that constant velocity for anot
borishaifa [10]

Answer:

The magnitude of the object's average velocity is 9.74 m/s (9.80 m/s without any intermediate rounding).

Explanation:

Hi there!

The average velocity is calculated as the displacement of the object divided by the time it takes the object to do that displacement.

The displacement is calculated as the distance between the final position of the object and the initial position. <u>In this problem</u>, the displacement is equal to the traveled distance because the object travels only in one direction:

a.v = Δx/t

Where:

a.v = average velocity.

Δx = displacement = final position - initial position

t = time

So, let's find the distance traveled while the object was accelerating. For that, we will use this equation:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the object at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

In this case, since the object is initially at rest, v0 = 0. If we place the origin of the frame of reference at the point where the object starts moving, then x0 = 0. So, the equation of the position of the object after a time t will be:

x = 1/2 · a · t²

x = 1/2 · 1.90 m/s² · (6.60 s)²

x = 41.4 m

The object traveled 41.4 m during the first 6.60 s.

Now, let's find the rest of the traveled distance.

When the velocity is constant, a = 0. Then, the equation of position will be:

x = x0 + v · t

Let's place now the origin of the frame of reference at the point where the object starts traveling at constant velocity so that x0 = 0:

x = v · t

The velocity reached by the object during the acceleration phase is calculated as follows:

v = v0 + a · t   (v0 = 0 because the object started from rest)

v = 1.90 m/s² · 6.60 s

v = 12.5 m/s

Then, the distance traveled by the object at a constant velocity will be:

x = 12.5 m/s · 8.50 s

x = 106 m

The total traveled distance in 15.1 s is (106 m + 41.4 m) 147 m.

Then the displacement will be:

Δx = final position - initial position

Δx = 147 m - 0 = 147 m

and the average velocity will be:

a.v = Δx/t

a.v = 147 m / 15.1 s

a.v = 9.74 m/s

The magnitude of the object's average velocity is 9.74 m/s (9.80 m/s without any intermediate rounding).

8 0
3 years ago
Find the time it takes for each object to accelerate from 0m/s to 40 m/s when pushed with 100N of force
Ivan

Answer:

40s

Explanation:

Given:

F=100N

V=40m/s and 0

force=change in momenton

F=mv-mu

t=40(100-0)/100

t=40/1

t=40s

4 0
3 years ago
A 2kg bowling ball is 2.5 meter off the ground on a post when it falls. Just before it reaches the ground, it is traveling 7m/s.
shutvik [7]
<span>The mechanical energy is conserved.

I hope this helps, good luck! :)</span>
7 0
3 years ago
Human blood consists of blood groups A, B, and O. However, there is one more blood group, AB, which contains alleles A and B in
Arturiano [62]
The answer is Codominance, AB blood cells inherit both A and B blood types so they are codominance
3 0
3 years ago
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