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2 years ago

10

Please help me with the question below

1 answer:

vampirchik [111]2 years ago

6 0

Answer:

a cold air mass and a warm air mass merge together

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Suppose you lived in the crater Copernicus on the side of the Moon facing Earth.

Wittaler [7]

Answer and Explanation:

In case, I lived in the Crater Copernicus on Moon's side facing the Earth then:

On moon, as it orbits the Earth, it takes 29 and a half days to complete one cycle of sunrise and sunset. So, the would rise once in 29 and a half day.
The moon orbits the Earth in such a way that the its same side faces the Earth always which concludes that the Earth is overhead every time resulting in no Earth rise or Earth set on Moon.
Due to the thin atmosphere, it can't impart any specific color to the sky on the moon as a result of which the moon's sky is always black and hence, stars can be seen every time.

5 0

3 years ago

A thin ring of radius 73 cm carries a positive charge of 610 nC uniformly distributed over it. A point charge q is placed at the

kow [346]

Answer:

q = - 93.334 nC

Explanation:

GIVEN DATA:

Radius of ring 73 cm

charge on ring 610 nC

ELECTRIC FIELD p FROM CENTRE IS AT 70 CM

E = 2000 N/C

Electric field due tor ring is guiven as

$E = \frac{KQx}{[x^2+ R^2]^{3/2}}$

$E = \frac{9\time 10^9 \times 610\times 10^[-9} 0.70}{(0.70^2 + 0.73^2)^{3/2}}$

E1 = 3714.672 N/C

electric field due to point charge q

$E =\frac[kq}{x^2}$

$E = \frac{9\times 10^9 \times q}{0.70^2}$

$E2 = 1.837\times 10^{10}\times q$

now the eelctric charge at point P is

E = E1 + E2 $2000 = 3714.672 + 1.837\times 10[10} \times q$

solving for q

q = - 93.334 nC

7 0

3 years ago

What force keeps our atmosphere from floating out into space?

Tems11 [23]

The answer is C, gravity

4 0

2 years ago

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When a current of 0.015 A passes through human body at 240 volts p.d it<br><br>causes

geniusboy [140]

Explanation:

Given that,

Current, I = 0.015 A

Voltage, V = 240 volts

We need to find the resistance. Using Ohm's law we can find it as follows :

$V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{240}{0.015}\\\\R=16000\ \Omega$

So, When a current of 0.015 A passes through human body at 240 volts p.d it causes 16000 ohms of resistance.

3 0

3 years ago

Which statement describes something that should always be done at the end of a calculation?

Reika [66]

Answer:

C) Check that the numerical answer is reasonable and the units are what you expected.

Explanation:

5 0

3 years ago

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