Answer: There is two (PO4) in the formula
Explanation:
Just be aware of the difference between numbers to the right and left: 5Mg3 means there are a total of 5 Mg (if 3 is a number in the bottom left) the 3 in (PO4) means there are 3 PO4 but because of the 2 it could mean there are 6.
Depends if the elements are separated
Answer:
I don't knowI think it will break
The wave height is equal to twice the amplitude of the wave.
The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.
The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.
Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.
Learn more here:brainly.com/question/21431500
Translation
A tractor pulling a cart loaded with sugar cane travels down the straight path of a farm at a speed of 20 km / h. If at 3:00 p.m.you pass the Finca Las Margaritas, what time will you arrive at the Las Ilusiones farm, located on the same road, if the distance between the two farms is 60 km
Answer:
6.00 pm
Explanation:
Speed is given by dividing distance by time and expressed as s=d/t. Making time the subject of the formula then t=d/s where s is the speed, d is distance covered and t is the time taken. Substituting 20 km/h for s and 60 km for d then t=60/20=3 hours
Adding 3 hours to 3 pm we get 6pm
Therefore, the time to reach the destination if the speed is constantly maintained is 6.00 pm
Answer:
The near point of an eye with power of +2 dopters, u' = - 50 cm
Given:
Power of a contact lens, P = +2.0 diopters
Solution:
To calculate the near point, we need to find the focal length of the lens which is given by:
Power, P = 
where
f = focal length
Thus
f = 
f = 
= + 0.5 m
The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.
Now, by using lens maker formula:
where
u = object distance = 25 cm = 0.25 m = near point of a normal eye
u' = image distance
Now,
Solving the above eqn, we get:
u' = - 0.5 m = - 50 cm
