Explanation:
I don't think the coat will make any difference
Answer:
2.66 m/s² .
Explanation:
Initial velocity , u = 0 m/s
Final Velocity , v = 8 m/s
Time Taken , t = 3 s
So , Acceleration = (v-u)/t = (8 m/s - 0 m/s) /3 sec . = 8/3 m/s² = 2.66 m/s²
Answer:
a) 90 kJ
b) 230.26 kJ
Explanation:
The pressure at the first point
= 10 bar —> 10 x 102 = 1020 kPa
The volume at the first point
= 0.1 m^3
The pressure at the second point
= 1 bar —> 1 x 102 = 102 kPa
The volume at the second point
= 1 m^3
Process A.
constant volume V = C from point (1) to P = 10 bar.
Constant pressure P = C to the point (2).
Process B.
The relation of the process is PV = C
Required
For process A & B
(a) Sketch the process on P-V coordinates
(b) Evaluate the work W in kJ.
Assumption
Quasi-equilibrium process
Kinetic and potential effect can be ignored.
Solution
For process A.
V=C
There is no change in volume then

The work is defined by

║
V║limit 1--0.1
90 kJ
Process B
PV=C
By substituting with point (1) C = 10^2 x 1= 10^2
The work is defined by

║
ln(V)║limit 1--0.1
=230.26 kJ
This frequency definition leads us to the simplest frequency formula: f = 1 / T . f denotes frequency and T stands for the time it takes to complete one wave cycle measured in seconds. The SI frequency unit is Hertz (Hz), which equals 1/s (one cycle per second)

Hope It Helps!
Answer:
mass of liquid = total mass - mass of container
m = 52000kg - 200kg
m = 519800
D = m/v
D = 519800/160
D = 3,248.75 kgm-³