34 + 3 ⋅ 5 = ____. (Input whole numbers only.)

2 answers:

6 0

To solve this question, you need to use the procedure "PEMDAS" in this equation, multiplication would come first, so you find the product of 3 and 5 which will equal 15. Then, take the product of those numbers and add them to 34. The answer should be 49.

P.S. PEMDAS:
P - Parenthesis ()
E - Exponents x_2
M - Multiplication X
D - Division /
A - Addition +
S - Subtraction -

Natalija [7]4 years ago

5 0

PEDMAS says that we do the multiplication first
34+3*5
34+15
49

Hope this helps :)

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70 POINTSS!!!! URGETT PLS HELP!! Vectors t = −5i + 2j, u = −3i + 7j, and v = 8i + 20j are given.

LUCKY_DIMON [66]

The angle between the vectors t and u is 45°. And the vector t and vector w are orthogonal to each other.

<h3>What is a vector?</h3>

The quantity which has magnitude, direction and follows the law of vector addition is called a vector.

The vectors are given below.

t = −5i + 2j, u = −3i + 7j, and v = 8i + 20j

Part A: Then the angle between vectors t and u will be

$\cos \theta = \dfrac{\overrightarrow{a} \cdot \overrightarrow{b}}{|\overrightarrow{a}| + |\overrightarrow{b}|}$

Then we have

cos θ = [(−5i + 2j)(−3i + 7j)] / [√{(-5²) + 2²} + √{(-3)² + 7²}]

cos θ = 1 / √2

θ = 45°

Part B: c is a scalar

If $\rm \overrightarrow{\rm v} = (a, b)$ , then $\rm c\overrightarrow{\rm v} = c(ca, cb)$

Let c = 2, then we have

$\overrightarrow{\rm w} = c\overrightarrow{v}\\\\\overrightarrow{\rm w} = (2*8, 2*20)\\\\\overrightarrow{\rm w} = (16, 40)$

Part C: Use the dot product to determine if t and w are parallel or orthogonal.

$\overrightarrow{\rm t} \cdot \overrightarrow{\rm w} = (-5, 2)(16, 40)\\\\ \overrightarrow{\rm t} \cdot \overrightarrow{\rm w} = -5*16+ 2*40\\\\ \overrightarrow{\rm t} \cdot \overrightarrow{\rm w} = -80+ 80\\\\ \overrightarrow{\rm t} \cdot \overrightarrow{\rm w} = 0$