Answer:
(0, 33) : Yes
(4.8, 30.5) : Yes
Step-by-step explanation:
height of at least 24 ft : y >= 24
horizontal distance of no more than 10 ft. : 0 <= x <= 10
The vertical height must be at least three times as high as the horizontal distance. No rocket should go higher than 33 ft.:
y >= 3x and y <= 33
So Constraints:
24 <= y <= 33
y >= 3x
0 <= x <= 10
Now check to see if those coordinate points meet all the constraints
(0, 33) : Yes
(4.8, 30.5) : Yes
(9, 26) : No (because 26 is less than (3 * 9) = 27)
(4, 36)
: No (because 36 > 33, must be 24 <= y <= 33)
(2, 22): No (because 22 <24, must be 24 <= y <= 33)
$11.25 because 10 times 1.125 is equal to 11.25
3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)
From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . . (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)
(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5
From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3
x = 3, y = 0.5, z = -3.5
Tanya run 50 yards across the diagonal of the rectangular field.
<u>Step-by-step explanation</u>:
Step 1 :
- Length of the rectangular field = 40 yards
- width of the rectangular field = 30 yards
Step 2 :
Measure of the diagonal = √(length^2 + width^2 )
Step 3 :
Diagonal = √(40^2 + 30^2 )
= √(1600 + 900)
= √2500
= ±50
Step 4 :
Since distance cannot be negative, The measure of diagonal = 50 yards.
∴ Tanya runs diagonally across a rectangular field is 50 yards.
