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8090 [49]
3 years ago
8

Draw the organic product of the following nucleophilic substitution reaction. include the appropriate hydrogen atoms in your str

uctural formula.
Chemistry
1 answer:
AnnyKZ [126]3 years ago
7 0
Since you did not give the reactions, i cannot give the answers. 

In organic and inorganic chemistry, nucleophilic substitution is a fundamental class of reactions in which an electron rich nucleophile selectively bonds with or attacks the positive or partially positive (+ve)charge of an atom or a group of atoms to replace a leaving group; the positive or partially positive atom is referred to as an electrophile. The whole molecular entity of which the electrophile and the leaving group are part is usually called the substrate.

The most general form for the reaction may be given as the following:

<span>Nuc: + R-LG → R-Nuc + LG<span>:</span></span>
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A sample of a compound made entirely from copper and oxygen was found to have a total mass of 0.143 g the mass of copper in the
tensa zangetsu [6.8K]

Mass of Oxygen: 0.0159 grams

Moles of Oxygen: 9.94x10^-4

To find the mass of oxygen, subtract the mass of copper from the total mass.

0.143-0.1271=0.0159

There are 0.0159 grams of Oxygen.

To find how many moles there are, divide the given amount of oxygen by the molar mass (atomic mass) of oxygen because that mass is the same as one mole of oxygen.

Molar mass of Oxygen: 16.00

0.0159/16.00=9.94*10^{-4}

There are 9.94*10^-4 moles of Oxygen.

6 0
1 year ago
Help please I need help with these two questions answer truthfully get brainliest?!!​
irina1246 [14]

Answer:

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value of x=7

5 0
3 years ago
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Pressure is defined as _______.1
Yakvenalex [24]

Answer:the perpendicular force per unit area

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Explanation:

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7 0
2 years ago
How many chloride ions are needed to cancel the 2+ charge of magnesium in magnesium chloride?
mario62 [17]
As the charge of chloride is 1- , two chloride ions are needed to cancel the 2+ charge in MgCl2
5 0
3 years ago
Help !! Im not sure how to do this ​
7nadin3 [17]
1)The third equation must be halved.
H20–>H2+1/2O2
So ΔΗ3=483.6/2
2)The second equation must be halved and reversed.
CO2–>CO+1/2O2
So ΔΗ2=-(-566)/2=566/2

And now :
C+O2–>CO2
CO2–>CO+1/2O2
H2O—>H2+1/2O2
(You add them)
C+H2O—>CO+H2
ΔΗrxn=ΔΗ1+ΔΗ2’+ΔΗ3’=-393.5+283+241,8=131,3
4 0
3 years ago
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