Answer:
Place the experiments on a scale
Explanation:
If you place two of the same experiments on a scale, and cover one with a cup, the one with the cup will "lose" mass, while the other won't, due to the cup being a "containment field" I guess you could call it.
Answer:
OH⁻ = 1.05×10⁻¹³ M
Explanation:
Given data;
H₃O⁺ = 9.61×10⁻² M
OH⁻ = ?
Solution:
First of all we will calculate the pH.
pH = -log [H⁺]
pH = -log [H₃O⁺]
Because pH is also the hydronium ion concentration.
pH = -log [ 9.61×10⁻²]
pH = 1.02
It is known that,
pH + pOH = 14
1.02 + pOH = 14
pOH = 14 - 1.02
pOH = 12.98
Concentration of OH⁻.
pOH = -log [OH⁻]
12.98 = -log [OH⁻]
OH⁻ = 10∧-12.98
OH⁻ = 1.05×10⁻¹³ M
Answer: both the different glycosidic linkages of the molecules and the different hydrogen bonding partners of the individual chains.
Explanation:
Glycogen is a polysaccharide of glucose which is a form of energy storage in fungi, bacteria and animals. Glycogen is primarily stored in the liver cells and skeletal muscle.
The difference in interchain stability between the polysaccharides glycogen and cellulose is due to the different glycosidic linkages of the molecules and the different hydrogen bonding partners of the individual chains.
For this question we use Boyle's law which states the relationship between pressure and volume. At constant temperature, pressure of a gas is inversely proportional to volume of a gas.
PV = k
where P-pressure, V - volume and k - constant
Therefore P1V1 = P2V2
where parameters for 1st instance are on the left side and parameters for the 2nd instance are on the right side.
183 ml x 310 mmHg = 90.6 ml x P2
P2 = 183 x 310 / 90.6
= 626.16 mmHg
pressure required is 626.16 mmHg
Answer: Option (D) is the correct answer.
Explanation:
An electric circuit works well when all the connections are complete but if any of the connections in the circuit is loose or disconnected then it is possible that current will not flow from the circuit.
Therefore, when Jenna removed one of the clips on the battery then circuit becomes incomplete and as a result there will no flow of current.
Thus, we can conclude that the electrical energy would stop because the circuit is incomplete.