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Step2247 [10]
4 years ago
9

The molecular formula of morphine, a pain-killing narcotic, is c17h19no3. what is the molar mass? what is the mass of 6.02 x 102

4 molecules of morphine?
Chemistry
1 answer:
kati45 [8]4 years ago
5 0
<span>Molar mass is the mass of one mole of a substance, it can be a chemical element or a compound. It is a characteristic of each pure substance. We calculate it by adding up all of the masses of the atoms involved in the compound. We calculate as follows:
                   atomic mass         total mass
C     17        12.01 g/mol          204.17 g/mol
H     19          1.01 g/mol           19.19 g/mol
N      1         14.00 g/mol            14.00 g/mol
O      3         16.00 g/mol            48.00 g/mol
------------------------------------------------------------
Molar mass                           = 285.36 g/mol

</span><span>What is the mass of 6.02 x 10^24 molecules of morphine?

</span>6.02 x 10^24 molecules ( 1 mol / 6.02x10^23 molecules) ( 285.36 g/mol) = 2853.6 g morphine
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The balanced reaction between aqueous potassium hydroxide and aqueous acetic acid is ________. KOH (aq) + HC2H3O2 (aq) → OH- (l)
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KOH (aq) + HC2H3O2 (aq) → H2O (l) + KC2H3O2 (aq)

Explanation:

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KOH (aq) + HC2H3O2 (aq) → H2O (l) + KC2H3O2 (aq)

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How many inches are in 450 cm ?
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3 0
3 years ago
48.0 mL of 1.70 M CuCl2(aq) and 57.0 mL of 0.800 M (NH4)2S(aq) are mixed together to give CuS(s) as a precipitate. The other pro
artcher [175]

Answer:

The concentration of the Cu(II) ion is 0.777M

Explanation:

Step 1: Data given

Volume of  1.70 M CuCl2 = 48.0 mL = 0.0480 L

Volume of 0.800 M (NH4)2S = 57.0 mL = 0.0570 L

Step 2: The balanced equation

CuCl2 (aq) + (NH4)2S (aq) → 2 NH4Cl (aq) + CuS (s)

Step 3: Calculate moles CuCl2

moles CuCl2 = 0.0480 L * 1.70 M=0.0816 moles

Step 4: Calculate moles (NH4)2S

moles (NH4)2S = 0.0570 L * 0.800 M = 0.0456 moles

Step 5: Calculate the limiting reactant

The ratio between CuCl2 and (NH4)2S is 1 : 1 so (NH4)2S is the limiting reactant . IT will completely be consumed (0.0456 moles).

CuCl2 is in excess. There will remain 0.0816 - 0.0456 = 0.0360 moles

Step 6: Calculate moles of CuS

For 1 mol CuCl2 we need 1 mol (NH4)2S to produce 2 moles of NH4Cl and 1 mol CuS

For 0.0456 moles we'll produce 0.0456 moles CuS

Step 7: Calculate moles of Cu(II)ion

There remains 0.0360 moles CuCl2.

There will be 0.0456 moles CuS produced

Total moles Cu^2+ = 0.0816 moles

Step 8: Calculate concentration of Cu(II) ion

Concentration = moles / volume

Concentration = 0.0816 moles / (0.048+0.057)

Concentration = 0.777 M

The concentration of the Cu(II) ion is 0.777M

7 0
4 years ago
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