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Alex17521 [72]
3 years ago
11

F(x)=x^2-14x+33 enter the quadratic function in factored form

Mathematics
1 answer:
juin [17]3 years ago
5 0

Answer:

F(x)=(x-11)(x-3)

Step-by-step explanation:

we have

F(x)=x^{2} -14x+33

Find the zeros of the function

F(x)=0

0=x^{2} -14x+33

Group terms that contain the same variable, and move the constant to the opposite side of the equation

-33=x^{2} -14x

Complete the square. Remember to balance the equation by adding the same constants to each side

-33+49=x^{2} -14x+49

16=x^{2} -14x+49

Rewrite as perfect squares

16=(x-7)^{2}

square root both sides

(x-7)=(+/-)4

x=(+/-)4+7

x=(+)4+7=11

x=(-)4+7=3

so

The factors are

(x-11) and (x-3)

therefore

F(x)=(x-11)(x-3)

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