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lesya [120]
3 years ago
10

Please help me on number 2

Mathematics
1 answer:
krok68 [10]3 years ago
6 0
Bottom right hand one, as the two on the left ask for the same thing, it's in terms of x regardless of whether it says so or not, and the upper right is the same as the upper left, except the equation is flipped over the equal.
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2 years ago
What is the area of the figure below ?
Airida [17]

Answer:

Step-by-step explanation:

Area of the figure = area of the down triangle + area of trapezium + area of the upper triangle

Down triangle:

Base b = 8 in

Height = 6 in

Area = \frac{1}{2}bh\\=\frac{1}{2}*8*6\\\\=4*6

= 24 in²

Trapezium:

bases a = 4 in & b = 6 in

Height h =  5 in

Area=\frac{(a+b)h}{2}\\\\=\frac{(4+6)*5}{2}\\\\=\frac{10*5}{2}\\\\=5*5

= 25 in²

Area of the upper triangle:

Base b = 6 in

Height = (8 - 5) = 3 in

Area=\frac{1}{2}bh\\\\=\frac{1}{2}*6*3\\\\=3*3

= 9 in²

Area of the figure = 24 + 25 + 9 = 58 in²

3 0
3 years ago
Read 2 more answers
What is the solution set of 2x^2 - 3x = 5?<br> (-1,-5/2)<br> (-1, 5/2}<br> (1.-5/2}
earnstyle [38]

Answer:

(-1, 5/2)

Step-by-step explanation:

That is what I got

5 0
3 years ago
Read 2 more answers
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