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zalisa [80]
3 years ago
11

What equation is graphed in this figure?

Mathematics
2 answers:
aniked [119]3 years ago
5 0

Based on the graph, the slope is -3, and the y-intercept is 1. So your equation should be:

y = -3x + 1

The answer is C

y + 2 = -3(x - 1)

y + 2 = -3x + 3

y = -3x + 1

patriot [66]3 years ago
3 0
The answer is y=-3x+1 so it would b c:)
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a car reduced its speed in a ratio of 2 to 3 if the final speed was 90 km per hour then what was the original speed.​
Licemer1 [7]

Answer:

Orginal Speed is 135

Step-by-step explanation:

The ratio of final speed: original speed is

\frac{2}{3\\}

We know that 90 km is it final speed so, we set up a proportion

\frac{2}{3} =90/x

2x=270\\x=135

8 0
2 years ago
_ 1. If U = {1,2,3,4,5) and A= {2,4} then A' should be?
kirza4 [7]

If U={1,2,3,4,5) and A={2,4) then A' should be

Ans» d.{1,3,5}

4 0
3 years ago
The number of typing errors made by a typist has a Poisson distribution with an average of two errors per page. If more than two
wlad13 [49]

Answer: 0.6767

Step-by-step explanation:

Given : Mean =\lambda=2 errors  per page

Let X be the number of errors in a particular page.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that a randomly selected page does not need to be retyped is given by :-

P(X\leq2)=P(0)+P(1)+P(2)\\\\=(\dfrac{e^{-2}2^0}{0!}+\dfrac{e^{-2}2^1}{1!}+\dfrac{e^{-2}2^2}{2!})\\\\=0.135335283237+0.270670566473+0.270670566473\\\\=0.676676416183\approx0.6767

Hence, the required probability :- 0.6767

6 0
3 years ago
Solve for x in the equation
Viktor [21]

Answer:

{x}^{2}  + 2x + 1 = 17 \\  {x}^{2}  + 2x - 16 = 0 \\ x =  \frac{ - b± \sqrt{ {b}^{2}  - 4ac} }{2a}  \\ x =  \frac{ - 2± \sqrt{68} }{2}  \\ x =  \frac{ - 2±2 \sqrt{17} }{2 }  \\ x =  - 1± \sqrt{17}

5 0
3 years ago
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

3 0
3 years ago
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