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jok3333 [9.3K]
3 years ago
12

Nojo is 5 years older then jacob . the product of their ages is 84 . now old is noj

Mathematics
1 answer:
mixer [17]3 years ago
5 0
We can make two simple equations to express their ages to each other, then solve for one of the variables. Let n be Nojo's age and j be Jacob's age.

n(j) = 84
n - 5 = j
Use substitution to get only one variable in an equation.

n (n - 5) = 84
n^2 - 5n = 84

Since we have n to the power of 2, this equation has two possible answers, but since we are given four possible answer, just substitute them in the equation until one makes the left side equal 84.

<span>n^2 - 5n = 84
</span>12^2 - 5 (12) = 84
144 - 60 = 84
84 = 84

The answer is C = 12
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if u know how to put these from least to greatest you are a boss square root of 5, 3.7, 1/2, -4, -9/4
dimulka [17.4K]

-4, -9/4, 1/2, square root of 5 (which is 2.23), 3.7

5 0
3 years ago
Given the functions:<br> g(n) = 3n - 5<br> f(n) = n2 + 50<br> Find:<br> (g+f)(8)
puteri [66]

Answer:

(g + f)(8) =133

Step-by-step explanation:

Given

g(n) = 3n - 5

f(n) = n^2 + 50

Required

(g + f)(8)

This is calculated as:

(g + f)(n) =g(n) + f(n)

So, we have:

(g + f)(n) =3n - 5 + n^2  +50

Substitute 8 for n

(g + f)(8) =3*8 - 5 + 8^2  +50

(g + f)(8) =24 - 5 + 64  +50

(g + f)(8) =133

7 0
3 years ago
One thousand five hundred dollars is invested in two different accounts paying 4% and 5% interest. A total of $67 interest is ea
tiny-mole [99]
.04x+.05 (1500-x)=67
Solve for x
X=800 at 4%...answer

1500-800=700 AT 5%

Hope it helps:-)

8 0
3 years ago
Does anyone know the answer?
Lorico [155]

Answer:

n = 59

Step-by-step explanation:

Since the difference between consecutive terms is constant, then the sequence is arithmetic.

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

Given

a_{10} = 40, then

a₁ + 9d = 40 → (1)

Given

a_{20} = 20, then

a₁ + 19d = 20 → (2)

Subtract (1) from (2) term by term

10d = - 20 ( divide both sides by 10 )

d = - 2

Substitute d = - 2 in (1)

a₁ - 18 = 40 ( add 18 to both sides )

a₁ = 58

The sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2}[2a₁ + (n - 1)d ]

Here a₁ = 58, d = - 2 and S_{n} = 0, thus

\frac{n}{2}[ ( 2 × 58) - 2(n - 1)] = 0

\frac{n}{2}( 116 - 2n + 2) = 0

Multiply through by 2

n(118 - 2n) = 0

Equate each factor to zero and solve for n

n = 0

118 - 2n = 0 ⇒ - 2n = - 118 ⇒ n = 59

However, n > 0 ⇒ n = 59

3 0
3 years ago
What is the quadrant of 0 6?
SSSSS [86.1K]

Answer:

it depends im pretty sure that you mean y and x cord  so answer is 0 x 6 y

Step-by-step explanation:

or 0 X so width or y height 6 Y

8 0
1 year ago
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