Answer:
The two roots of the quadratic equation are

Step-by-step explanation:
Original quadratic equation is 
Divide both sides by 9:

Add
to both sides to get rid of the constant on the LHS
==> 
Add
to both sides

This simplifies to

Noting that (a + b)² = a² + 2ab + b²
If we set a = x and b =
we can see that
= 
So

Taking square roots on both sides

So the two roots or solutions of the equation are
and 

So the two roots are

and

Answer:
B. 12^3 - 12^2 - 11
Step-by-step explanation:
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