ANSWER THIS NOWWWWWWWWW!!!!!!!!!!!!!!!!

2 answers:

8 0

A,b,d & e are all major. I think thats correct...because We are more worried about our water & air..& land poluution. Which what all four mentioned...hope i helped

Alchen [17]2 years ago

5 0

<span>A) Release of carbon emissions from cars into the air
D) Ground water affected by a nearby landfill

</span>

You might be interested in

A pharmacist receives a shipment of 22 bottles of a drug and has 4 of the bottles tested. If 6 of the 22 bottles are contaminate

romanna [79]

Explanation:

A hypergeometric distribution as a function of statistical distribution where members from two groups are analysed, without replacing those members. Unlike binomial distributions, in which the probability remains the same for each trial, in hypergeometric distributions, these members are not replaced- each trial's probability affects the probability within next trial.

This is used in the process of random sampling and as a means of quality control in statistics; for example selecting members of a sports team from a mixed population of boys and girls.

Hypergeometric Formula..,

For a population consisting of N items, k are successes. And a random sample from that population consisting of n items, x of which are successes.

∴ hypergeometric probability is:

h(x; N, n, k) = [ kCx ] [ N-kCn-x ] / [ NCn ]

this distribution always has...

its mean= n * k / N .
its variance is n * k * ( N - k ) * ( N - n ) / [ N2 * ( N - 1 ) ] .

Thus….

Total number of bottles = 22

Number of contaminated bottles = 6

Number of tested bottles = 4

X= a random variable representing the number of contaminated bottles selected for the test.

N = 22

K = 6

n = 4

The probability mass function, f(x), is given by...

P(X=x)) = [ kCx] [ N-kCn-x ] / [ NCn ] x= 0,1,2,3,...,n

= $\frac{[6 C 1] [22-6 C 4-1]}{[22 C 4]}$

$\frac{C\left \ {{k=6} \atop {x=1}} \right. C\left \ {{22-6} \atop {4-1}} \right. }{C \left \ {22} \atop {4}} \right. }$

$Cxk= C14= 4!(1!(4 - 1)!)^{-1}= 24(6)^{-1}= 4\\Cn-xN-k=C\left \ {{22-6} \atop {4-1}} \right. } =16!(4!(16-4)!)^{-1}\\(CnN)^{-1}=(C \left \ {{y=22} \atop {x=6}} \right. ) ^{-1}=[22!(6!(22-6)!)^{-1}]^{-1}$