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2 years ago

11

Find the sum (3x^2+5x-8)+(5x^2-13x-5)

2 answers:

Norma-Jean [14]2 years ago

8 0

No need to fear I'll help you get through this problem :D

Okay so this is the original problem, let's work down from it....

(3x² + 5x - 8) + (5x² - 13x - 5)

**** Remember we need to add only the values that have like variables of the same exponents ****

<u>(8x² - 8x - 13)</u><u /> <----- this will be the answer you will get when you add the values together....

I hope this helps you understand this problem! :D

<u>Please vote me for Brainliest!!!</u><u />

Radda [10]2 years ago

3 0

<span>8x^2-8x-13 is the correct answer </span>

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If point P(3,10) is reflected across the line y=1, what are the coordinates of it's reflection image ?

aliya0001 [1]

<span>If point P(3,10) is reflected across the line y=1, the coordinates of it's reflection image is (3,-8)

Answer is C.
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3 0

2 years ago

Read 2 more answers

In the game of roulette, a player can place a $4 bet on the number 29 and have a 1/38 probability of winning. If the metal bal

creativ13 [48]

Answer:

The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.

Step-by-step explanation:

Consider the provided information.

It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.

The probability of winning is 1/38. So, the probability of loss is 37/38.

Now, find the expected value of the game to the player as shown:

$E(x)=(140)\times \frac{1}{38}+(-4)\times \frac{37}{38}$

$E(x)=\frac{140-148}{38}$

$E(x)=\frac{-8}{38}=-$0.2105$

Hence, the expected value of the game to the player is -$0.2105.

Now find the expect to loss if played the game 1000 times.

1000×(-$0.2105)=-$210.5

Therefore, the expected loss if played the game 1000 times is -$210.5.

5 0

3 years ago

Pleaseee help me solve the function

schepotkina [342]

Answer:

$f(x) = \frac{3 {(2)}^{2} - 2 }{2(2) + 3} = \frac{12 - 2}{7} = \frac{10}{7}$

3 0

3 years ago

PLEASE HELP with3,4,5,6 <br> DUE IN 20 min

Alika [10]

Answer:

3.

$volume \ of \ cone = \frac{1}{3}\pi r^2h = \frac{1}{3}*3.14*6*6*15 = 3.14*36*5 = 565.2cm^3$

4.

$volume \ of \ cone = \frac{1}{3}\pi r^2 h = \frac{1}{3} *3.14* 12*12*20 = 3.14*12*4*20 = 3014.4cm^3$

5.

$volume \ of \ sphere = \frac{4}{3} \pi r^3 = \frac{4}{3}*3.14 * 3*3*3* = 4*3.14*9 = 113.0cm^3$

6.

$diameter = 13cm\\\\radius = 6.5cm\\\\volume \ of \ sphere = \frac{4}{3} \pi r^3= \frac{4}{3} *3.14*6.5*6.5*6.5 = 1149.8cm^3$

6 0

2 years ago

I don't really understand this problem

yKpoI14uk [10]

Complementary angles add up to 90 (there should be a right angle in the diagram)

x+20+x+10 needs to equal 90 where x=30

Left angle is measured 30+20=50 degrees

Angle on the right is measured 30+10=40 degrees

4 0

2 years ago