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3 years ago

Find the sum (3x^2+5x-8)+(5x^2-13x-5)

2 answers:

8 0

No need to fear I'll help you get through this problem :D

Okay so this is the original problem, let's work down from it....

(3x² + 5x - 8) + (5x² - 13x - 5)

**** Remember we need to add only the values that have like variables of the same exponents ****

(8x² - 8x - 13) <----- this will be the answer you will get when you add the values together....

I hope this helps you understand this problem! :D

Please vote me for Brainliest!!!

Radda [10]3 years ago

3 0

8x^2-8x-13 is the correct answer

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How do you Graph the function f(x) = -3(2)x on the axes

GaryK [48]

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6 0

3 years ago

Read 2 more answers

The population of a certain community is known to increase at a rate proportional to the number of people present at time t. If

attashe74 [19]

Answer:

$t=7.85 years$

Step-by-step explanation:

We can write this rate as an ordinary differential equation.

$\frac{dP}{dt}=aP$

Where a is proportional constant, P the population variable, and t the time.

$\frac{dP}{P}=adt$

Integrating each side of the equation.

$\int \frac{dP}{P}=\int adt$

$ln(P)=at+c$

$P=e^{at+c}$

$P=e^{c}e^{at}=Ce^{at}$

To find C we need to use the initial condiction, it means evaluae P at t=0.

$P_{0}=Ce^{0}=C$

$P=P_{0}e^{at}$

Now, we use the sentence the population has doubled in 5 years.

$2P_{0}=P_{0}e^{a5}$

We can find "a" in this condition.

$2=e^{a5}$

$ln(2)=a5$

$a=\frac{ln(2)}{5}$

$a=0.14$

Finally, let's find how long will it take to triple.

$3P_{0}=P_{0}e^{0.14t}$

$3=e^{0.14t}$

$t=\frac{ln(3)}{0.14}$

$t=7.85 years$

I hope it helps you!

4 0

2 years ago

Which situation can be modeled using the equation 5x+3=27

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

SAT verbal scores are normally distributed with a mean of 433 and a standard deviation of 90. Use the Empirical Rule to determin

laila [671]

34% of the scores lie between 433 and 523.

Solution:

Given data:

Mean (μ) = 433

Standard deviation (σ) = 90

Empirical rule to determine the percent:

(1) About 68% of all the values lie within 1 standard deviation of the mean.

(2) About 95% of all the values lie within 2 standard deviations of the mean.

(3) About 99.7% of all the values lie within 3 standard deviations of the mean.

$$Z(X)=\frac{x-\mu}{\sigma}$

$$Z(433)=\frac{433-\ 433}{90}=0$

$$Z(523)=\frac{523-\ 433}{90}=1$

Z lies between o and 1.

P(433 < x < 523) = P(0 < Z < 1)

μ = 433 and μ + σ = 433 + 90 = 523

Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.

i. e. $((\mu-\sigma) \ \text{to} \ (\mu+\sigma))=68\%$

Here μ to μ + σ = $\frac{68\%}{2} =34\%$

Hence 34% of the scores lie between 433 and 523.

8 0

3 years ago

You are selling a mobile app for $10 per user per month.if you get 7 users every month starting with 10 in the first month.how m

Ahat [919]

Selling price of app per user = $10 per month

Total no. of user in first month = 10

To tal no. of user added per month = 7

We have to find how much money is earned in one year

So the formula is n/2 * (2a +(n-1)d)

Here we have n = 12 which is total no. of months

a = 100 , which is money earned in one month

d = 70 , which is increase in money earned per month

So money earned in a year comes out to be 5820

4 0

3 years ago