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Maksim231197 [3]
3 years ago
11

What is the equation of the line passing through the point (1,2) and (-2,5)

Mathematics
1 answer:
vlabodo [156]3 years ago
4 0
y=-x+3
simply plot the two points, draw a line and find the slope and y intercept
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The temperature at a mountain base camp was −3 degrees Celsius on Monday. Tuesday morning, the temperature was 2 degrees Celsius
kotegsom [21]
It is -3 to start off with, on Monday. On Tuesday morning it would be -3 - 2 degrees, = -5 degrees. By Tuesday evening it was 4 degrees lower than in the morning, so -5 - 4 degrees = -9 degrees on Tuesday evening.

Hope this helps xox :)
3 0
3 years ago
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For f(x) = 4x+1 and g(x) = x^2 -5, find (f-g)(x)
d1i1m1o1n [39]

Answer:

(f-g)(x) is given by -x^2+4x+6

Step-by-step explanation:

4 0
2 years ago
Charlie runs a book rental business. He currently charges $3 per book and rents out an average of 38 books a day.
liberstina [14]

Answer:

b(x) = (3+0.5x) (38-4x)

Step-by-step explanation:

Let the generated revenue per day be b(x)

Let x be the number for every 50cents($0.5) price increase

Formula to be used to generate the revenue generated is expressed using the formula:

b(x) = Price × Quantity

Next is to derive the price and quantity function in terms of x.

For the price:

If he currently charges $3 per book

Let derive the price function for the model and x number of price increase for every 50 cents, then

Price = ($0.5 of x)+$3

Price = $3+$0.5x

Price = $(3+0.5x)

For the quantity:

Number of books rent out per day = 38

If for every 50cents increase in rental price x, the average business can expect to lose 4 rentals a day, then the total lost per quantity = 4x

Quantity per time = Number of books rent out daily - loss on each book

Quantity = $(38-4x)

Next is to substitute the price and quantity function into the revenue formula above:

Revenue = Price × Quantity

Revenue = (3+0.5x)(38-4x)

Hence the equation that models this scenario, where b(x) is the revenue generated and x is the number of 50 price increases is b(x) = (3+0.5x)(38-4x)

7 0
3 years ago
3.From Question 2 If Rachel's car can drive 18 miles per gallon of gas, and she has to drive 90
maria [59]

Answer:

90miles divided by 18 miles is 5 gallons

8 0
3 years ago
**50 POINTS!!! WILL GIVE BRAINLIEST!!!**
lorasvet [3.4K]
<h3>Given</h3>

The values of two houses (in thousands of dollars)

\left[\begin{array}{c|cccc}\text{year}&0&1&2&3\\\text{value 1}&286&294.58&303.4174&312.51992\\\text{value 2}&286&295&304&313\end{array}\right]

<h3>Find</h3>

A) the nature of the function, linear or exponential, that can be used to model the value after x years

B) the actual function f(x) that can be used in each case

C) f(25) for each house. Is there a significant difference?

<h3>Solution</h3>

A) The oddball numbers give you a clue immediately that the value of house 1 will be best modeled by an exponential function.

The value of house 2 is increasing steadily at 9,000 per year, so is modeled by a linear function.

B) The ratio of values from a given year to the year before for house 1 is

... 294.58/286 = 1.03

A check for other years reveals the same ratio, so the exponential function can be written for house 1 as

... f(x) = 286·1.03^x . . . . . value of house 1

In part A we determined the year-to-year difference in value for house 2 is 9,000. That is the slope of the linear function. Then (in thousands), that function is

... f(x) = 286 +9x . . . . . value of house 2

C) After 25 years, the house values are (in thousands of dollars)

f_1(25)=286\cdot 1.03^{25}\approx 598.82049\\\\f_2(25)=286+9\cdot 25=511.00000

The value of house 1 has more than doubled in the same time that the value of house 2 has increased by about 79%. This is a significant difference.

___

An exponential function will always outperform a linear function over a long enough time period.

5 0
3 years ago
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