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4 years ago

Line segment AB is tngent to circle O at A. Which type of triangle is always formed when points A, B and O are connected?

1 answer:

7 0

The best and most correct answer among the choices provided by your question is the first choice or letter A.

<span> When points A, B and O are connected, it forms a right triangle.</span>

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Which equation would best help solve the following problem? Hideki throws a baseball ball upward with an initial velocity of 12

Digiron [165]

The total time of flight of a projectile motion is calculated through the equation,
t = 2v₀sinФ/g
Substituting the known values,
t = (2)(12 m/s)(sin 90)/9.8 m/s²
t = 2.45 s
Thus, the total flight time of the ball in the atmosphere is 2.45 s.

8 0

3 years ago

WILL MARK BRAINLEIST

lina2011 [118]

Answer:

decrease by 50%

Step-by-step explanation:

$\frac{0.4x}{0.8y} =\frac{x}{2y}$

Decreased by 60% = (100%-60%)x = 0.4x.

Decreased by 20% = (100%-20%)x = 0.8x.

$\frac{x}{y}$ initial fraction, and we can see that denominator will increase 2 times, so fraction will decrease 2 times, or decrease by 50%.

6 0

3 years ago

If on the unit circle C, the distance from P(1, 0) to the point T ( 4/5 , 3/5 ) is x, determine the coordinates of the point at

AveGali [126]

Answer:

$(\frac{4}{5}, -\frac{3}{5} )$

Step-by-step explanation:

The point P(1,0) and T $(\frac{4}{5}, \frac{3}{5} )$ are on the unit circle C and the arc length from P to T is x.

Let us assume that point P - x i.e. the point obtained by moving clock wise direction along the circle from P is T'.

Because of the symmetry of the circle about the coordinate axes, the x-coordinate of point T' will be $\frac{4}{5}$ and the y-coordinate will be $-\frac{3}{5}$ .

So, coordinates of T' are $(\frac{4}{5}, -\frac{3}{5} )$ .

Here we must notice that point T' is the reflection point of T with respect to X-axis. (Answer)

3 0

3 years ago

An environmentalist wants to find out the fraction of oil tankers that have spills each month. Step 2 of 2 : Suppose a sample of

rewona [7]

Answer:

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 333 tankers is drawn. Of these ships, 257 did not have spills.

333 - 257 = 76 have spills.

This means that $n = 333, \pi = \frac{76}{333} = 0.228$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 - 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.199$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 + 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.257$

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

6 0

3 years ago

What is 40 to 80 in percentage change

Whitepunk [10]

Answer:

100 percent

Step-by-step explanation:

The value 40 increases to 80 meaning it doubles its value by one hundred percent.

4 0

3 years ago

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