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2 years ago

11

Given A is between Y and Z YA = 5.5, AZ = 2x, and YZ = 41.5 =, find AZ

2 answers:

STatiana [176]2 years ago

8 0

Answer:

$AZ=36$

Step-by-step explanation:

We have been given that point A is between point Y and Z such that $YA=5.5$ , $AZ=2x$ and $YZ=41.5$ .

Using our given information, we can set an equation as:

$YZ=YA+AZ$

Substitute given values:

$41.5=5.5+2x$

Switch sides:

$5.5+2x=41.5$

$5.5-5.5+2x=41.5-5.5$

$2x=36$

Since $AZ=2x$ , so the length of segment AZ is 36 units.

morpeh [17]2 years ago

4 0

YZ = YA + AZ
41.5 = 5.5 + AZ
AZ = 41.5 - 5.5
AZ = 36

So, your final answer is AZ = 36

Hope this helps!

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your automobile insurance semiannual premium is 750 and you have 1050 deductible per incident. In a particularly bad year, you h

nataly862011 [7]

Answer:

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Step-by-step explanation:

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3 years ago

What is the measure of the compliment of an angle if it’s supplement is 145

Ivahew [28]

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180-145=35
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3 0

2 years ago

Read 2 more answers

Last questions, plz help

Goryan [66]

Answer:

9. $a_n=7+6n$

10. $a_n=a_{n-1}+7$

Step-by-step explanation:

9. Given the sequence

$13, 19, 25, ...$

In this sequence,

$a_1=13\\ \\a_2=19\\ \\a_3=25\\ \\...$

Note that

$a_2-a_1=19-13=6\\ \\a_3-a_2=25-19=6,$

then the common difference in this sequence is $d=6$

You have

$a_1=13\\ \\d=6,$

then the explicit formula is

$a_n=a_1+(n-1)d\\ \\a_n=13+(n-1)\cdot 6\\ \\a_n=13+6n-6\\ \\a_n=7+6n$

10. Given the sequence

$-10,-3, 4, 11, ...$

In this sequence,

$a_1=-10\\ \\a_2=-3\\ \\a_3=4\\ \\a_4=11\\ \\...$

Note that

$a_2-a_1=-10-(-3)=-10+3=-7\\ \\a_3-a_2=-3-4=-7\\ \\a_4-a_3=11-4=7,$

then the common difference in this sequence is $d=7$

You have

$a_1=-10\\ \\d=7,$

then the recursive formula is

$a_n=a_{n-1}+d\\ \\a_n=a_{n-1}+7$

5 0

2 years ago

Urgent help needed...............

andreyandreev [35.5K]

Answer:

Option b is correct

$\{x | x \neq \pm 7, x\neq 0\}$ .

Step-by-step explanation:

Domain is the set of all possible values of x where function is defined.

Given the function:

$h(x) = \frac{9x}{x(x^2-49)}$

To find the domain of the given function:

Exclude the values of x, for which function is not defined

Set denominator = 0

$x(x^2-49) = 0$

By zero product property;

$x = 0$ and $x^2-49= 0$

⇒x = 0 and $x^2 =49$

⇒x = 0 and $x = \pm 7$

Therefore, the domain of the given function is:

$\{x | x \neq \pm 7, x\neq 0\}$

7 0

2 years ago

Read 2 more answers

80,607.202 rounded to the nearest tens place is

postnew [5]

It’s 80,610 if you really mean the tens place.
If you mean the one tenths place then it’s 80,607.2

5 0

2 years ago