Since the base is a regular quadrilateral, each of its 4 sides must have length
s = P/4
s = (60 cm)/4 = 15 cm
The area of one lateral face is the product of side length and height.
A = s×h
105 cm² = (15 cm)×h
Then the height of the prism is
h = (105 cm²)/(15 cm) = 7 cm
The area of the base is then
B = s²
B = (15 cm)² = 225 cm²
The volume of the prism is the product of its base area and height.
V = Bh
V = (225 cm²)×(7 cm) = 1575 cm³
The volume is 1575 cm³.
Answer:
- 2x² + 7x + 1
Step-by-step explanation:
f(x) - g(x)
= x² + 2x - 6 - (3x² - 5x - 7) ← distribute parenthesis by - 1
= x² + 2x - 6 - 3x² + 5x + 7 ← collect like terms
= - 2x² + 7x + 1
The request is to find the intersection of the two sets. By definition, the intersection of two sets is another set, composed by all the elements appearing in both sets.
In other words, 
is the set of all elements that P and Q have in common.
P contains all the numbers from 0 to 9, V contains all the odd numbers between 1 and 19. So, their intersection will be the odd numbers between 0 and 9, i.e.
3 repeating digits are there
