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Novay_Z [31]
3 years ago
12

3. Water flows through a pipe at a rate of 10 gallons per minute. How many gallons

Mathematics
2 answers:
horsena [70]3 years ago
6 0

Answer:

600 gallons

Step-by-step explanation:

10 time 1 is ten

1 minute is 1/60 of an hur so multiply it by 60

60 times 10 is 600

diamong [38]3 years ago
3 0

1 minute = 10gal

60minutes = 10×60 gal.

1 hour = 600 gallons

Happy to help!Please tell me if you understand!

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Please helppp with this math question &lt;333
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Answer:

The average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

Step-by-step explanation:

We are given the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1

We need to find average rate of change.

The formula used to find average rate of change is : Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}

We have b=-1 and a=-11

Finding g(b) = g(-1)

g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9

Finding g(a) = g(-11)

g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29

Finding average rate of change

Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1

So, the average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

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