1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitry_Shevchenko [17]
3 years ago
5

How do you solve for a and b?

Mathematics
2 answers:
natali 33 [55]3 years ago
5 0
You need to isolate b on one side of the equation then divide both side by h finally move b on the other side of the equation by subtracting it from both sides of the equation and then you have what b equals to
Allisa [31]3 years ago
3 0
Here you go, hope it helped!

You might be interested in
A local pizza shop has a membership program for frequent buyers. The membership costs $10 per month and members get a discounted
dmitriy555 [2]

Answer:

Monthly cost = $10 + $1.75x

Step-by-step explanation:

Given the following :

Membership cost = $10 per month

Discounted price for members = $1.75 per slice of pizza

If Autum purchased the membership, the monthly cost for x slices of pizza

Monthly cost of x slices will be :

Membership cost + (discounted price * number of slices)

Monthly cost = $10 + ($1.75 * x)

Monthly cost = $10 + $1.75x

8 0
3 years ago
Solve |3x + 3|= 27
Alenkasestr [34]

Answer:

d.x=-8 and x=-10

Step-by-step explanation:

4 0
3 years ago
5. Line l has an equation y = 2x – 4. Write the
Vladimir [108]

Answer:

y=2x-1

Step-by-step explanation:

7 0
3 years ago
CP is equal to 200 SP is equal to 100 find the profit or loss​
ioda

Answer:

100

Step-by-step explanation:

if SP>CP,

It is profit [SP - CP = Profit]

if CP>SP,

It is loss   [CP - SP = Loss]

Here in the question CP>SP so,

loss = CP - SP

       =200 - 100

       = 100

5 0
2 years ago
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.676.6
faltersainse [42]

Answer:

Step-by-step explanation:

Researchers measured the data speeds for a particular smartphone carrier at 50 airports.

The highest speed measured was 76.6 Mbps.

n= 50

X[bar]= 17.95

S= 23.39

a. What is the difference between​ the carrier's highest data speed and the mean of all 50 data​ speeds?

If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps

b. How many standard deviations is that​ [the difference found in part​ (a)]?

To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation

Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations

c. Convert the​ carrier's highest data speed to a z score.

The value is X= 76.6

Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51

d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly​ high, is the​ carrier's highest data speed​ significant?

The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.

I hope it helps!

3 0
3 years ago
Other questions:
  • Determine the value of<br> b2 - 4ac<br> when:<br> a=0<br> b=4<br> C=100
    6·1 answer
  • Please I need help the answer please
    10·2 answers
  • ‼️Name the vertex and sides of the angle below
    15·1 answer
  • In VWX the measure of
    7·1 answer
  • Express the fraction 11/30 in decmail form
    15·2 answers
  • Which of the following statements is NOT true? All whole numbers are rational numbers. All whole numbers are rational numbers. A
    9·1 answer
  • What number is 50 % of 6/5<br> ​
    14·1 answer
  • Identify any x-intercepts for the graph below .
    11·1 answer
  • Can help me with math please and thank you
    6·2 answers
  • A dinner plate has a circumference of 100.48 cm. What is the area of the dinner plate? Use 7 = 3.14.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!