Answer:
I18 - xI such that x < 18.
ok, first let's what happens if x = 18:
I18 - xI = I18 - 18I = 0
So, at the moment we have the condition:
I18 - xI > 0.
now, if x is a really large negative number, suppose, x = -100
I18 + 100I = I118I = 118
So, as x can freely move in the negative range, we can see that I18 - xI can be any positive number, so the only restriction that we have is:
I18 - xI > 0.
This means that the domain is:
D = (-∞, 18)
and the range is:
R = (0, ∞)
The answer is negative twenty five. By the way, if that is you in the picture, you are beautiful.
What are you specifially looking for? simplified it would be 10 and as a fraction 10 over 1
Answer:
unit rate:2 y-intercept:6
Step-by-step explanation:
Answer:
(6 , -1)
Step-by-step explanation:
2x+ y = 11 ----------------(I)
y = 11 - 2x --------------------(II)
Multiply the whole equation by 2
x - 10y = 16 --------------------(III)
Substitute y = 11- 2x in equation (III)
x - 10(11 - 2x) = 16
x - 110 + 20x = 16
21x - 110 = 16
21x = 16 +110
21x = 126
x = 126/21
x = 6
Plugin x = 6 in equation (II)
y = 11 - 2*6
y = 11 - 12
y = -1
