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disa [49]
4 years ago
6

I need help 6-18 can someone explain how you got the answer thank you

Mathematics
1 answer:
Dvinal [7]4 years ago
3 0
Q -  6-18
awnser is -12
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(DO NOT ANSWER IN A LINK) (PLS ONLY ANSWER CORRECT) A function is defined by f (x) = 6 x + 1.5. What is f(2.5)?
Amanda [17]

Answer:

f(5) = 16.5

Step-by-step explanation:

Substitute x = 2.5 into f(x) , that is

f(2.5) = 6(2.5) + 1.5 = 15 + 1.5 = 16.5

4 0
2 years ago
How Many L/min are in 105.6 L/h
Irina18 [472]
To change it into minutes you want to do unit analysis

105.6 L / h × 1h / 60 minutes

so 105.6L times 1h divided by 60 gives you:

1.76L / minute

4 0
3 years ago
Graph the points ( 0, 2 ), ( 6, 2 ), ( 7, 4 ), ( 1, 4 ) and connect the points in order to create a parallelogram. What is the p
boyakko [2]

Answer: 16, rational

Step-by-step explanation: because its a real number

7 0
3 years ago
Please help if u cannot skip
posledela

The statement that is true about the function is D. it is discontinuous and non-differentiable at x = 3.

<h3>How to determine which statement is true?</h3>

To determine which statement is true, we need to know the conditions for continuity and differentiablity of a function.

<h3>Conditions for continuity and differentiablity of a function.</h3>
  • For a function f(x) to be continuous at a point x = a, then both the left hand limit of f(x) and the right hand limit of f(x) as x → a must be equal. That is \lim_{x \to a^{-} } f(x) =  \lim_{x \to a^{+} } f(x). So,  \lim_{x \to a^{} } f(x) must exist since  \lim_{x \to a^{-} } f(x) =  \lim_{x \to a^{+} } f(x) =  \lim_{x \to a^{} } f(x)
  • Also, for a function to be differentiable at a point x = a, it must also exist at x = a

So, since f(x) = {x² - 1 if -1 ≤ x ≤ 3 and x²/3 if 3 < x ≤ 8}

From the equality on the first condition,we see that f(x) is exists at x = 3 but is not continuous since f(x) changes to another function when x > 3. So,left hand limit of f(x) and the right hand limit of f(x) as x → 3 are not equal.

That is \lim_{x \to 3^{-} } f(x) \neq   \lim_{x \to 3^{+} } f(x) . Thus, the function is discontinuous at x = 3.

For differentiability, both conditions must be met. Since only one condition is met, it is non-differentiable.

So, the function is discontinuous and non-differentiable at x = 3.

So, the statement that is true about the function is D. it is discontinuous and non-differentiable at x = 3.

Learn more about continuity of a function here:

brainly.com/question/24177259

#SPJ1

4 0
2 years ago
Find the perimeter and the area of the polygon with the given vertices.
Nimfa-mama [501]

9514 1404 393

Answer:

  • perimeter: 16 units
  • area: 15 square units

Step-by-step explanation:

The dimensions of the rectangle are 3 by 5 units, so the perimeter is ...

  P = 2(W+L) = 2(3+5) = 16 . . . units

__

The area is ...

  A = WL = (3)(5) = 15 . . . square units

3 0
3 years ago
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