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3 years ago

Solve the inequality. Graph the solution. −1.4 ≤ h + 1.1

Mathematics

1 answer:

Tcecarenko [31]3 years ago

7 0

Answer:

Step-by-step explanation:

- 1.4 < h + 1.1

Solve for H. Get H by itself by subtracting 1.1 on both sides of the equation.

-1.4 - 1.1 = - 2.5

-2.5 < h

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A burro is standing near a cactus. The burro is 58 in. tall. His shadow is 4 ft long. The shadow of the cactus is 8 ft long. Wha

Sever21 [200]

To find the height of the cactus, make a ratio.

58 inches divided by 4 feet equals x inches divided by 8 feet.

58/4 = x/8

14.5 = x/8

116 = x

The height of the cactus is 116 inches.

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3 years ago

If 3:y=18:24 find y.

VashaNatasha [74]

y = 4

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1 year ago

Any clue on this one please help

barxatty [35]

Yes, because they both have the same slope, and a translation doesn't have an affect of the slope. Both slopes are 1, because they are going +1x and +1y, or 1/1 which = 1.

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4 years ago

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Find u, v , u , v , and d(u, v) for the given inner product defined on Rn. u = (0, −4), v = (5, 3), u, v = 3u1v1 + u2v2

tigry1 [53]

Answer:

$=-12$

$d(u,v)=2\sqrt{31}$

Step-by-step explanation:

We are given that inner product defined on $R_n$

$=3u_1v_1+u_2v_2$

u=(0,-4),v=(5,3)

We have to find the value of <u,v> and d(u,v)

We have $u_1=0,u_2=-4,v_1=5,v_2=3$

Substitute the value then we get

$=3(0\cdot5)+(-4)(3)=-12$

Now, $d(u,v)=\left \|v-u\right \|$

Using this formula we get

$d(u,v)=\left \| (5,7) \right \|=\sqrt{3(5)^2+(7)^2}=\sqrt{75+49}=\sqrt{124}$

$d(u,v)=2\sqrt{31}$

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3 years ago

The vertex of the parabola below is at the point (-4,-2) wich of the equations below could be the one for this parabola

MrRissso [65]

The parabola with with a vertex at (-4,-2) represents any member of parabolas with the equation $y(x)=a(x+4)^2-2$ where $a$ is any real number with the exception that $a\neq 0$ .

The reason any equation of the form $y(x)=a(x+4)^2-2$ works is that there are an infinite number of parabolas with a vertex at (-4,-2). All of these parabolas are formed by applying some transformation that involves a vertical translation of -2 and a horizontal translation of -4 on the parabola $y=x^2$ . The different variations are archived by varying the constant $a$ . When $a$ is negative, the parabolas will face downwards. When $a$ is negative, the parabolas will be face downwards.

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3 years ago

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