The box has volume
11 in × 3 in × <em>x</em> in = 33<em>x</em> in³
and surface area
2 (11 in × 3 in + 11 in × <em>x</em> in + 3 in × <em>x</em> in) = (66 + 28<em>x</em>) in²
The volume and area have the same value if
33<em>x</em> = 66 + 28<em>x</em>
Solve this equation for <em>x</em> :
33<em>x</em> - 28<em>x</em> = 66
5<em>x</em> = 66
<em>x</em> = 66/5 = 13.2
Answer:
68
Step-by-step explanation:
I just know I was in class with my teacher
Answer: 23in squared
Step-by-step explanation:
9 plus 4 plus 10
Answer:
12
Step-by-step explanation:
t/9=16/12
12t=144
t=12
You would do 120/300 = p/100 and you would get 40%
