How do you solve an equation that looks like this?
2 answers:
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Answer:
<em>AB = 7.35 cm</em>
Step-by-step explanation:
From the attachment,
In ΔDEF,
DF = GH-(GD+FH) = 6 - (2+3) = 1 cm
DE = 2+3 = 5 cm (sum of two radius)
Applying Pythagoras theorem,
In ΔCDI,
DI = GH-(GD+IH) = 6 - (2+1.5) = 2.5 cm
CD = 2+1.5 = 3.5 cm (sum of two radius)
Applying Pythagoras theorem,
AB = EF + CI =
Answer:
(x + 6)² + 16 = 0
Step-by-step explanation:
To complete the square we will first need to get our equation to look like: x² + bx = c
Here we have x² + bx + c = 0 → x² + 12x + 52 = 0
- First we need to subtract our c, in this case 52, from both sides to get x² + 12x = -52
- We then need to add
to both sides of the equation
- Here our b value is 12, so plugging this into our formula we get
- Adding 36 to both sides our equation becomes: x² + 12x + 36 = -52 + 36
- Then combining like terms on the right side we get x² + 12x + 36 = -16
- Now making our left side of the equation into a perfect square we get: (x + 6)² = -16
- Finally adding the 16 to both sides of the equation we get: (x + 6)² + 16 = 0