I sgree with the perosn above, theres no picture attached it aint showing up
Answer: 0.665.
Step-by-step explanation:
60% of the bags are from supplier A, and 95% of them are undamaged.
40% of the bags are from supplier B, and 75% of them are undamaged.
Then, the number of undamaged bags from supplier A is:
0.6*0.95 = 0.57 or 57%
from B is:
0.4*0.75 = 0.3 or 30%
This means that the percentage of undamaged bags is:
57% + 30% = 87%.
Then, the probability that an undamaged bag is from supplier A is equal to the percentage of undamaged bags that came from supplier A (57%) and the total percentage of undamaged bags (87%) this is:
P = 57%/87% = 0.655 or 65.5%
Then the probability that an undamaged bag comes from supplier A is 0.665.
Answer:
Step-by-step explanation:
Let's put in some numbers to make this easier to understand.
Let's say she has to travel 20 km.
On Monday, she travels at 4 kph. This takes 5 hours.
On Tuesday she travels 25% faster, at 5 kph. This takes 4 hours.
To figure percent reduction we take
100 % * (old - new) / old
100 % * (5 hr - 4 hr ) / 5 hr
100 % * 1 hr / 5 hr
100 % * 0.20
20% reduction.
Answer:
If you were to order them least to greatest, it would be:
4/8 < 9/16 < 4/6 < 3/4
If you were to order them greatest to least, it would be:
3/4 > 4/6 > 9/16 > 4/8
Answer:
interval=(15.085,14.9515)
Step-by-step explanation:
Table:
CI Z
85% 1.440
90% 1.645
95% 1.960
In order to find the interval/estimate of hours per week students study we consider the formula given below:
Interval=X±
where:
X is the mean hours
Z is the value from Z distribution table of Confidence Interval
n is the sample size of students
S is the standard deviation
X=15, Z=1.645, S=2.3hours, n=78
Interval=15±
Interval=15±0.0485
interval=(15.085,14.9515)
