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3 years ago

Find the domain of the function. f(x) = x² - 9x - 15 What is the domain off?

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

4 0

The domain of the function is all real numbers because it is a quadratic equation

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What is the distance between -6 and -3 on a number line?

Ira Lisetskai [31]

I think it's 3 but idk I'm not good at math

7 0

3 years ago

Read 2 more answers

Richard filled 3-gallon jug with fruit punch.

Alecsey [184]

Answer:

About 11.4

Step-by-step explanation:

There are 3.78541178 liters in a gallon.

Round that up to the nearest 100 and you get 3.8

Multiply 3.8 by 3.

You get 11.4

7 0

3 years ago

A mail courier charges a base fee of $6.95 plus $7.60 per package being delivered. If x represents the number of packages delive

castortr0y [4]

Since 7.6 is the cost per package, and x represents the number of packages, the expression 7.6x would represent the cost for the packages. Once we add the base fee, we get the equation:

y = 7.6x + 6.95

Hope this helps.

5 0

3 years ago

Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how

astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was <u>$95,300</u>.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be $x.$

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

$x=A\times (1+\frac{r}{100})^{11}$

$x=75000\times (1+\frac{2.2}{100})^{11}$

$x=75000\times (1+0.022)^{11}$

$x=75000\times (1.022)^{11}$

$x=75000\times 1.2704$

$x=95280.$

<em>The amount of house after eleven years to the nearest hundred dollars is $95,300.</em>

Therefore, when Aria sold her house after eleven years it worth was $95,300.

3 0

3 years ago

Please hurry. Solve the equation

Lelu [443]

The value of x is $5\sqrt[3]{25}$ .

Solution:

Given expression is $-7=8-3 \sqrt[5]{x^{3}}$ .

Switch both sides.

$8-3 \sqrt[5]{x^{3}}=-7$

Subtract 8 from both side of the equation.

$8-3 \sqrt[5]{x^{3}}-8=-7-8$

$-3 \sqrt[5]{x^{3}}=-15$

Divide by –3 on both side of the equation.

$$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}$

$\sqrt[5]{x^{3}}=-5$

To cancel the cube root, raise the power 5 on both sides.

$(\sqrt[5]{x^{3}})^5=(-5)^5$

$x^3=3125$

To find the value of x, take square root on both sides.

$\sqrt[3]{x^3}=\sqrt[3]{25}$

$x=5\sqrt[3]{25}$

Hence the value of x is $5\sqrt[3]{25}$ .

5 0

3 years ago