Step-by-step explanation:
whenever a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial. as an example, we'll find the roots of the polynomial..
x^5 - x^4 + x^3 - x^2 - 12x + 12.
the fifth-degree polynomial does indeed have five roots; three real, and two complex.
A=7d+13
A=7(4)+13
A= 28+13
A=41
Let x = the other rational number.
x(66/7) = (48/5)
Solve for x to find your answer.
Answer:
0=0
Step-by-step explanation:
6(2x+4)=4(3x+6)
Step 1: Simplify both sides of the equation.
6(2x+4)=4(3x+6)
(6)(2x)+(6)(4)=(4)(3x)+(4)(6)(Distribute)
12x+24=12x+24
Step 2: Subtract 12x from both sides.
12x+24−12x=12x+24−12x
24=24
Step 3: Subtract 24 from both sides.
24−24=24−24
0=0
