Quadrilateral abcd is a Trapezoid with and area of 20cm find the height of the Trapezoid h round to nearest tenth

You want to put a fence around your large yard. There are two companies that you have found to do the work. They have each given

dexar [7]

Answer:

STEP 1: See attached drawing on graph paper

STEP 2:

Length of segment 1 - 2 = 100 feet

Length of segment 2 - 3 = 89.44 ft.

Length of segment 3 - 4 = 186.82 ft.

Length of segment 4 - 5 = 120.83 ft.

Length of segment 5 - 1 = 136.01 ft.

STEP 3:

The perimeter of the property is 633.103 ft.

STEP 4:

The cost of fencing by Company 1 is $7597.24

The cost of fencing by Company 2 is $8246.55

Therefore, the company that provides the cheapest quote for fencing the property is Company 1

Step-by-step explanation:

STEP 1: See attached drawing on graph paper

STEP 2:

Therefore, we have

Length of segment 1 - 2 = √(8² + 6²) = 10 × 10 = 100 feet

Length of segment 2 - 3 = √(4² + 8²) = 4·√5× 10 = 40·√5 feet = 89.44 ft.

Length of segment 3 - 4 = √(5² + 18²) = √349 = 10·√349 feet = 186.82 ft.

Length of segment 4 - 5 = √(11² + 5²) = √146 = 10·√146 feet = 120.83 ft.

Length of segment 5 - 1 = √(11² + 8²) = √185 = 10·√185 feet = 136.01 ft.

STEP 3:

Therefore, the perimeter of the property = 100 + 89.44 + 186.82 + 120.83 + 136.01 = 633.103 ft.

STEP 4:

Hence the cost of fencing the property by Company 1 = $12 × 633.103 = $7597.24

The cost of fencing the property by Company 2 = $250 + $15 × 533.103 = $8246.55.

7 0

3 years ago

In triangle ABC, ∠ABC=70° and ∠ACB=50°. Points M and N lie on sides AB and AC respectively such that ∠MCB=40° and ∠NBC=50°. Find

Sever21 [200]

Answer:

∠NMC = 50°

Step-by-step explanation:

The interpretation of the information given in the question can be seen in the attached images below.

In ΔABC;

∠ A + ∠ B + ∠ C = 180° (sum of angles in a triangle)

∠ A + 70° + 50° = 180°

∠ A = 180° - 70° - 50°

∠ A = 180° - 120°

∠ A = 60°

In ΔAMN ; the base angle are equal , let the base angles be x and y

So; x = y (base angle of an equilateral triangle)

Then;

x + x + 60° = 180°

2x + 60° = 180°

2x = 180° - 60°

2x = 120°

x = 120°/2

x = 60°

∴ x = 60° , y = 60°

In ΔBQC

∠a + ∠e + ∠b = 180°

50° + ∠e + 40° = 180°

∠e = 180° - 50° - 40°

∠e = 180° - 90°

∠e = 90°

At point Q , ∠e = ∠f = ∠g = ∠h = 90° (angles at a point)

∠i = 50° - 40° = 10°

In ΔNQC

∠f + ∠i + ∠j = 180°

90° + 10° + ∠j = 180°

∠j = 180° - 90°-10°

∠j = 180° - 100°

∠j = 80°

From line AC , at point N , ∠y + ∠c + ∠j = 180° (sum of angles on a straight line)

60° + ∠c + ∠80° = 180°

∠c = 180° - 60°-80°

∠c = 180° - 140°

∠c = 40°

Recall that :

At point Q , ∠e = ∠f = ∠g = ∠h = 90° (angles at a point)

Then In Δ NMC ;

∠d + ∠h + ∠c = 180° (sum of angles in a triangle)

∠d + 90° + 40° = 180°

∠d = 180° - 90° -40°

∠d = 180° - 130°

∠d = 50°

Therefore, ∠NMC = ∠d = 50°

3 0

3 years ago

An article presents a study of health outcomes in women with symptoms of heart disease. In a sample of 115 women whose test resu

My name is Ann [436]

Answer:

z(s) is in the rejection region we reject H₀ μ₁ = μ₂ and support the claim that at CI 95 % the means of the two groups differs

Step-by-step explanation:

Sample 1:

Sise sample n₁ = 115

μ₁ = 169,9 mmHg

σ₁ = 24,8 mmHg

Sample 2:

Sise sample n₂ = 235

μ₂ = 163,3 mmHg

σ₂ = 25,8 mmHg

We can develop a test hypothesis for differences in means to investigate if the mean peak systolic blood pressure differs between these two groups

We will choose CI = 95 % then significance level α = 5 %

α = 0,05 α/2 = 0,025

z(c) for 0,025 is from z-table z(c) = 1,96

Test Hypothesis:

Null Hypothesis H₀ μ₁ = μ₂

Alternative Hypothesis Hₐ μ₁ ≠ μ₂

The alternative hypothesis tells us that the test is a two-tail test.

z(s) = ( μ₁ - μ₂ ) / √ σ₁²/n₁ + σ₂²/n₂

z(s) = ( 169,9 -163,3 ) / √ (24,8)² /115 + ( 25,8)²/235

z(s) = 6,6 / √5,35 + 2,83

z(s) = 6,6 / 2,86

z(s) = 2,30

Comparing |z(c)| and |z(s)|

z(s) > z(c)

z(s) is in the rejection region we reject H₀ μ₁ = μ₂ and support the claim that at CI 95 % the means of the two groups differs

6 0

3 years ago

Steps to scientific notation

chubhunter [2.5K]

1.Move the decimal place to the left to create a new number from 1 up to 10.
2.Determine the exponent, which is the number of times you moved the decimal.
3.Put the number in the correct form for scientific notation

3 0

3 years ago

Please help!!!! <br> Solve the following equation for m:<br> m/3=6

RSB [31]

Answer:

$\frac{m}{3} = 6 \\ m = 6 \times 3 \\ = 18$

5 0

3 years ago

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