Answer:
Step-by-step explanation:
Answer to Consider the area between the graphs x+6y=12 and x+4=y^2. ... This Can Be Computed As A Single Interval Where Alpha= Beta= And H(y)=
Answer:
A
Step-by-step explanation:
The answer would be -9/40
Here’s how you solve it!
Use PEMDAS through out the whole process
Anything that I should multiplied by 1 stays the same so you can multiply the 1 first so your equation looks like this:
3✖️1/8✖️(2/3➕2✖️2/3✖️(1/4➖6/5))
Now subtract the fractions that are in the parentheses, subtract 1/4➖6/5 so your equation looks like this:
3✖️1/8✖️(2/3➕2✖️2/3✖️(➖19/20))
Since a positive multiplied by a negative equals a negative change the sign so your equation should look like this:
3✖️1/8✖️(2/3➖2✖️2/3✖️19/20)
Then use the greatest common divisor and reduce it by 2
3✖️1/8✖️(2/3➖2/3✖️19/10)
Then reduce again
3✖️1/8✖️(2/3➖1/3✖️19/5)
Then multiply the two factors so it now looks like this:
3✖️1/8✖️(2/3➖19/15)
Now subtract what’s in the parentheses so you get this:
3✖️1/8✖️(➖3/5)
Since a positive multiplied by a negative equals a negative it will now look like this:
➖3✖️1/8✖️3/5
Now all you have to do left is calculate the product to get your answer:
-9/40
Hope this helps! :3
I hope this helps you
5 1/2=5.2+1/2=11/2
3.11/2
33/2
15 3/2
16,5
