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3 years ago

10

. The sum of three consecutive numbers is greater than 40. The inequality that represents this is x + x + 1 + x + 2 > 40. Whi

ch values of x hold true for the inequality?

1 answer:

Mrrafil [7]3 years ago

4 0

The closest you can get is 12.4.

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Solve for x in the figure below. Show your work.

ololo11 [35]

Answer:

19

Step-by-step explanation:

The square represents a right angle, 90 degrees, so all you do is subtract the 22 from 90. which is 68. 68 then is subtracted by 11, and you're left with 57. You then divide 57 by 3, because you have 3 x and you want to find x. And you get 19

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2 years ago

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2 years ago

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The Area is the width<span> times the </span>height<span>: A = w x h;
Then, 64 = w x h;
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2 years ago

MANY PTS AND BRAINLY FAST

Troyanec [42]

Answer:

Option C

Step-by-step explanation:

we have

$-6x^{2} -6x+12=0$

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$-6x^{2} -6x=-12$

step 2

Factor -6 leading coefficient'

$-6(x^{2} +x)=-12$

step 3

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Remember to balance the equation by adding the same constants to each side

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$-6(x^{2} +x+0.25)=-13.5$

step 4

Rewrite as perfect squares

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simplify

$(x+0.5)^{2}=2.25$

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3 years ago

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