Step-by-step explanation:
= -4c + 14
hence -4c + 14 is the answer ...
hope it helped !!
Because of the symmetry, we can just go from x=0 to x=2 to find the area between
<span>y = x^2 and y = 4 </span>
<span>that area = ∫4-x^2 dx from 0 to 2 </span>
<span>= [4x - (1/3)x^3] from 0 to 2 </span>
<span>= 8 - 8/3 - 0 </span>
<span>= 16/3 </span>
<span>so when y = b </span>
<span>x= √b </span>
<span>and we have the area as </span>
<span>∫(b - x^2) dx from 0 to √b </span>
<span>= [b x - (1/3)x^3] from 0 to √b </span>
<span>= b√b - (1/3)b√b - 0 </span>
<span>(2/3)b√b = 8/3 </span>
<span>b√b =4 </span>
<span>square both sides </span>
<span>b^3 = 16 </span>
<span>b = 16^(1/3) = 2 cuberoot(2) </span>
<span>or appr 2.52</span>
First, let's declare a variable
x = # of students
Now, let's create an equation to model the problem.
x * 0.273 = 125
Divide both sides by 0.273
x = 457.8 = 458 students.
Note, I rounded to the nearest whole number.
Answer : 1.4 x 10^-9
Step-by-step explanation:
0.0000000014
= 1.4 x 10^-9
ummm there's nothing attached
