Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways =
=126
=
=
D iaitu (beza sepunya)=T2(sebutan kedua)-T1(sebutan pertama)
A. 1/10000 because it is a 1/100 chance for each.
b. 1/100 because there are 10,000 options and 100 of them are the same options. Simplify for the answer.
Multiply all terms by 15
3x+3x= 10x+30
Combine like terms
6x=10x+30
Subtract 10x from both sides
-4x=30
Divide both sides by -4
x= -7.5
Final answer: -7.5