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ira [324]
3 years ago
8

What is the range of the function f(x) = –2|x + 1|?

Mathematics
2 answers:
sammy [17]3 years ago
8 0

Answer:

Range \rightarrow all real numbers less than or equal to 0 \rightarrow ( - ∞ , 0 ]

Step-by-step explanation:

beks73 [17]3 years ago
6 0

Answer:

Range \rightarrow all real numbers less than or equal to 0 \rightarrow ( - ∞ , 0 ]

Step-by-step explanation:

For visual understanding a graph of the  function is attached with the answer.

  • For calculating the range of any modulus function you need to know that if modulus is there across any function then the output will be always positive.

For example: x has a range of ( - ∞ , + ∞ ) but |x| has a range of [ 0 , + ∞ ). Similarly range of |x + 1| is [ 0 , + ∞ ).

  • If you multiply the modulus function with a negative sign then the output will always be negative.

For example: Range of |x| is [ 0 , + ∞ ) but range of -|x| is ( - ∞ , 0 ]. Similarly range of -|x + 1| is ( - ∞ , 0 ]

  • Range in this case won't be affected on multiplying a positive constant with the modulus function.

Therefore the range of f(x) = -2|x + 1| will be ( - ∞ , 0 ].

(NOTE : <em>[a,b] means all the numbers between 'a' and 'b' including 'a' and 'b'.</em>

<em>(a,b) means all the numbers between 'a' and 'b' excluding 'a' and 'b'.</em>

<em>(a,b] means all the numbers between 'a' and 'b' including only 'b' not 'a'.</em>

<em>[a,b) means all the numbers between 'a' and 'b' including only 'a' not 'b'.</em>

<em>{a,b} means only 'a' and 'b'.</em>

<em>{a,b] or (a,b} doesn't mean anything.</em> )

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(1, 3) represent a solution to the equation.
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The surface area of the prism below is 264 square units . Find the missing dimensions of this prism. ( picture is in the picture
nignag [31]

Answer:

The missing dimension is 4 units.

Step-by-step explanation:

In the given prism,

Of all the surfaces,

There are three rectangular surfaces and two triangular surfaces

<h2>Analyzing areas of rectangular surfaces:</h2>

1)The two rectangles with dimensions of 15 units and 5 units:

The area of each rectangle = Length of rectangle \times Breadth of rectangle

From the diagram,

Length of rectangle = 15 units,

Breadth of rectangle = 5 units.

Area of each rectangle = 15\times 5 ;

Area of each rectangle = 75 square units.

Sum of areas of the two rectangles = 2\times 75

Sum of areas of the two rectangles = 150 square units (equation 1)

2) The rectangle with the dimensions 15 units and 6 units:

The area of thus rectangle=  Length of rectangle \times Breadth of rectangle

From the diagram,

Length of rectangle = 15 units,

Breadth of rectangle = 6 units.

Area of the rectangle = 15\times 6 ;

Area of the rectangle = 90 square units. (equation 2)

From equation 1 and equation 2,

Therefore sum of areas of all rectangles in the prism = 150 + 90

Sum of areas of rectangles = 240 square units.

We also know,

Total surface area of the prism = Sum of areas of triangles + Sum areas of rectangles

Given, Total surface area of prism = 264 square units.

Therefore from the formula,

Sum of areas of triangles = Total surface area - sum of areas of reactangles

Sum of areas of triangles = 264 - 240

Sum of areas of triangles = 24 square units. (equation 3)

Let the missing dimension be 'h units'

<h2>Calculating sum of areas of triangles:</h2>

From diagram,both triangles are congruent,hence have the same area

Area of a triangle = \frac{1}{2}\times base\times height

From diagram,

Base = 6 units,

Height = h units.

Area of a triangle =\frac{1}{2}\times 6\times h = 3h square units.

Sum of the areas of both triangles = 3h+3h = 6h square units.

Using equation 3, we get

6h = 24;

h = \frac{24}{6}

Therefore,

h = 4 units.

Therefore,

The missing dimension is 4 units.

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