Answer:
63.5F
Step-by-step explanation:
Let x represent the temperature at the start of the experiment. Then the temperature at first check is (x -10.4F). The temperature at the second check is 1/3 that value, and is said to be 17.7F. This lets us write the equation ...
1/3(x -10.4F) = 17.7F
Multiplying by 3 gives ...
x -10.4F = 53.1F
x = 63.5F . . . . . . add 10.4F
The initial temperature of the liquid was 63.5F.
_____
<em>Additional comment</em>
Temperature is measured on an "interval scale." On such a scale, the value 0 is located arbitrarily. Concepts such as "1/3 of the temperature" have no meaning on such a scale. Here, we have to ignore that fact and assume the problem is about the numbers, not about any real temperature relationship in thermodynamic terms.
Simplifying
x = 6 + -4y
Solving
x = 6 + -4y
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Simplifying
x = 6 + -4y
Hope I Helped. Sorry If I'm Wrong.
Answer:
Rs 175
Step-by-step explanation:
Suppose the cost is x and at Rs150 the loss is 150-x (this should be a negative number).
At Rs200, the profit is 200-x.
So we have an equation: minus 150 minus x is equal to 200 minus x.
To solve the equation, the cost price X is Rs175.
Answer:
32 bags
Step-by-step explanation:
0.5 × 16 = 32
hope it helps
